Write the chemical equation and the Ka expression for the acid dissociation of each of the following acids in aqueous solution. First show the reaction with H+1aq2 as a product and then with the hydronium ion: (a) C6H5COOH

Video transcript

Hello, everyone. Today we have the falling problem. Give the chemical equation and acid dissociation expression for the reaction of Aquarius Trick Loro acetic acid producing protons also give the chemical equation for its reaction producing hydrogen ions. So try chloral acetic acid can associate as such. So it'll be an aqueous solution and it's going to react in a reversible reaction to form our protons as well as our try chloral acetate. And so the acid or the K expression or the acid dissociation expression is going to be equal to the concentration of products over reacting. And so our products are are protons. We're gonna multiply that by our Trick Loro acetate and then that's going to be divided by our concentration of our try chlor oh acetic acid. And so if we were to write a chemical equation with our hydrogen ions per being a product, it would look as such. So we would have our try Claro acetic acid once again in the acquis form, this time reacting with liquid water. And this is going to be yet another reversible reaction and it's going to form our hydro ni um ions. Yes, of course, as well. As our try chloral acetate as a byproduct. And so with that, we have our three answers are chemical equation, the acid association expression and the chemical equation wherein hydro name ions are produced overall, I hope this helped. And until next time.