Skip to main content
Ch.14 - Chemical Kinetics
Chapter 14, Problem 88

Suppose that a certain biologically important reaction is quite slow at physiological temperature 137 _x001E_C2 in the absence of a catalyst. Assuming that the collision factor remains the same, by how much must an enzyme lower the activation energy of the reaction to achieve a 1 * 10^5-fold increase in the reaction rate?

Verified step by step guidance
1
Step 1: Understand the Arrhenius equation, which relates the rate constant k of a reaction to the temperature T and the activation energy E_a: k = A * e^(-E_a/(RT)), where A is the pre-exponential factor, R is the gas constant, and T is the temperature in Kelvin.
Step 2: Recognize that the problem asks for the change in activation energy (ΔE_a) needed to increase the reaction rate by a factor of 1 * 10^5. This means the new rate constant k' is 1 * 10^5 times the original rate constant k.
Step 3: Set up the ratio of the new rate constant to the original rate constant using the Arrhenius equation: k'/k = (A * e^(-E_a'/(RT))) / (A * e^(-E_a/(RT))) = e^((E_a - E_a')/(RT)).
Step 4: Substitute the given rate increase factor into the equation: 1 * 10^5 = e^((E_a - E_a')/(RT)).
Step 5: Solve for the change in activation energy ΔE_a = E_a - E_a' by taking the natural logarithm of both sides: ΔE_a = RT * ln(1 * 10^5).
Related Practice
Textbook Question

The enzyme urease catalyzes the reaction of urea, 1NH2CONH22, with water to produce carbon dioxide and ammonia. In water, without the enzyme, the reaction proceeds with a first-order rate constant of 4.15 * 10-5 s-1 at 100 C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of 3.4 * 104 s-1 at 21 C. (c) In actuality, what would you expect for the rate of the catalyzed reaction at 100 C as compared to that at 21 C?

2128
views
Textbook Question

The activation energy of an uncatalyzed reaction is 95 kJ/mol. The addition of a catalyst lowers the activation energy to 55 kJ/mol. Assuming that the collision factor remains the same, by what factor will the catalyst increase the rate of the reaction at (a) 25 C

4095
views
1
rank
Textbook Question

The activation energy of an uncatalyzed reaction is 95 kJ/mol. The addition of a catalyst lowers the activation energy to 55 kJ/mol. Assuming that the collision factor remains the same, by what factor will the catalyst increase the rate of the reaction at (b) 125 °C?

1218
views
Textbook Question

Consider the reaction A + B → C + D. Is each of the following statements true or false? (b) If the reaction is an elementary reaction, the rate law is second order.

373
views
Textbook Question

Consider the reaction A + B → C + D. Is each of the following statements true or false? (c) If the reaction is an elementary reaction, the rate law of the reverse reaction is first order.

775
views
Textbook Question

The reaction 2 NO(g) + O2(g) → 2 NO2 (g) is second order in NO and first order in O2. When [NO] = 0.040 M, and 3O24 = 0.035 M, the observed rate of disappearance of NO is 9.3⨉10-5 M/s. (b) What is the value of the rate constant?

403
views