The enzyme urease catalyzes the reaction of urea, 1NH2CONH22, with water to produce carbon dioxide and ammonia. In water, without the enzyme, the reaction proceeds with a first-order rate constant of 4.15 * 10-5 s-1 at 100 C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of 3.4 * 104 s-1 at 21 C. (c) In actuality, what would you expect for the rate of the catalyzed reaction at 100 C as compared to that at 21 C?

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Hi everyone for this problem, it reads starch can be hydrolyzed in glucose in the presence of the amylase enzyme. The reaction takes place under very mild conditions in the presence of the enzyme, in the neutral solution at 25°C with the rate constant of 3.25 times 10 to the third inverse seconds. In the absence of the enzyme, the reaction takes place very slowly and under harsh reaction conditions in a highly acidic solution at 80 degrees Celsius with the rate constant of 7.84 times 10 to the negative two seconds, inverse if the un catalyzed reaction was carried out at 25 degrees Celsius instead of 80 degrees Celsius, would it take place faster or slower? So we want to answer this part right here Whether or not it's going to take place faster or slower. And we're looking at the temperature here 25°C instead of 80°C. So the rate of a chemical reaction always increases with temperature, reactions become slower at lower temperatures. If we reduce the temperature of the un catalyzed reaction, the rate of the reaction will decrease. So the answer to this question is that the reaction will proceed slower. Okay, that is the answer to this problem. And that's the end of this problem. I hope this was helpful

Verified Solution

Key Concepts

Enzyme Catalysis

Rate Constants and Temperature

First-Order Reactions