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Ch.14 - Chemical Kinetics

Chapter 14, Problem 53

Calculate the fraction of atoms in a sample of argon gas at 400 K that has an energy of 10.0 kJ or greater.

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Hi everyone for this problem it reads calculate the fraction of Xenon atoms having an energy of 6.40 kg per mole or greater at a temperature of 150°C. Okay, so our goal here is to calculate the fraction. Okay, and the fraction of an atom having specified energy is given by the equation fraction is equal to e raise to negative activation energy over R times T. Okay, so just based off of what we're given in the problem, we know that our activation energy is equal to 6.40 killer jewels. Permal, we know R is a constant and that constant is 8.314 jewels over mole times Kelvin and our temperature is equal to 150°. So we know that based off of what was given in the problem, we need to make sure our units match here. So looking at our our constant, we can see that our energy is and jewels and our temperature is in kelvin. So we need to convert our activation energy to jewels and our temperature to Calvin. So in one killer jewel There's 1000 jewels. Okay, so our killer jewels cancel and our activation energy and jules is 6400 jewels per mole. Now for our temperature to go from C to Kelvin we add 273.15. So this gives us a new temperature and Kelvin to be 423.15 Kelvin. So now we have everything we need to plug into our equation and all of our units match. So let's go ahead and plug in. So our fraction is going to equal e raise to negative jewels per mole over R times T. So 8.314 jewels over mole times kelvin times 423.15 kelvin. Okay, So we get our fraction is equal to E raised to the negative 1.82. Okay, so once we plug this into our calculator, we'll get our fraction is equal to 0.162. And that is our final answer. That's it for this problem. I hope this was helpful.
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Sucrose 1C12H22O112, commonly known as table sugar, reacts in dilute acid solutions to form two simpler sugars, glucose and fructose, both of which have the formula C6H12O6. At 23 C and in 0.5 M HCl, the following data were obtained for the disappearance of sucrose: Time (min) 3C12H22o11 4 1M2 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 (a) Is the reaction first order or second order with respect to 3C12H22O114?

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(a) What factors determine whether a collision between two molecules will lead to a chemical reaction?

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(b) Does the rate constant for a reaction generally increase or decrease with an increase in reaction temperature?

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(a) The activation energy for the isomerization of methyl isonitrile (Figure 14.6) is 160 kJ>mol. Calculate the fraction of methyl isonitrile molecules that has an energy equal to or greater than the activation energy at 500 K. (b) Calculate this fraction for a temperature of 520 K. What is the ratio of the fraction at 520 K to that at 500 K?

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Textbook Question

The gas-phase reaction Cl(g) + HBr(g) → HCl(g) + Br(g) has an overall energy change of -66 kJ. The activation energy for the reaction is 7 kJ. (a) Sketch the energy profile for the reaction, and label Ea and ΔE.

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The gas-phase reaction Cl(g) + HBr(g) → HCl(g) + Br(g) has an overall energy change of -66 kJ. The activation energy for the reaction is 7 kJ. (b) What is the activation energy for the reverse reaction?

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