In this video we're going to take a look at a particular Ester reaction called saponification. Now, under this reaction, the hydroxide ion, so OH- dissolved in water, reacts with an Ester. This reaction cuts or cleaves the Ester bond to create a carboxylate anion and an alcohol.
Now here, what is a carboxylate anion? Well, that's just the conjugate base form of a carbicilic acid. And here we consider this to be the opposite process of a sterification. Now, saponification. Here we have our Ester, and this here represents our Ester linkage. When we use OH- dissolved in water, so aqueous OH-, it's going to cut this bond. Here, cut this connection.
By cutting this connection, this oxygen gains an H to reform our alcohol and this carbonyl gains an -O. It becomes our carboxylate anion. So remember the carboxylate anion is the conjugate base of a carbasilic acid. Conjugate base just means we lose an H+. Losing an H+ is why that oxygen now is negatively charged, right? So keep this in mind when we encounter any type of saponification reaction.