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Ch.21 - Organic Chemistry

Chapter 21, Problem 76d

Draw the structure of each aldehyde or ketone. d. 4-heptanone

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Welcome back, everyone draw the plausible structure of two beats. And on, before we begin, we have to recall that whenever we want to draw a structure of a specific name, it is important for us to classify the compound. And if we look at our suffix, we have, which essentially represents a ketone and ketones have a general form of an alkyl group bonded to carbel that is bonded to another alkyl group, they can be the same, they can be different. Now, the number in front that specific t be known essentially tells us where the carbonel group is. So it tells us that carbon number two contains the carbonel group. And now what we want to do from here is identify our alkyl groups. In other words, we want to identify how many carbon atoms do we have in those alkyl groups? R one and R two. For that purpose, we're going to look at the name, it says bean. So the parent is butane, right? If we think about butane as an L cane, that's A or remembered L can. So we have a total of four carbon atoms in our parent, what we're going to do is draw a four member chain 1234. If we enumerate it from left to right, 1234, we want to locate carbon number two that contains the Kanal group. And this leaves us with our R two, which is the methyl substituent and R one which is the ethyl substituent overall. We have our structure which is two beats non and we can label it as our final answer. Thank you for watching.