Skip to main content
Ch.4 - Chemical Quantities & Aqueous Reactions
Tro - Chemistry: A Molecular Approach 4th Edition
Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831Not the one you use?Change textbook
All textbooksTro 4th EditionCh.4 - Chemical Quantities & Aqueous ReactionsProblem 65
Chapter 4, Problem 65

Consider the precipitation reaction: 2 Na3PO4(aq) + 3 CuCl2(aq) → Cu3(PO4)2(s) + 6 NaCl(aq). What volume of 0.175 M Na3PO4 solution is necessary to completely react with 95.4 mL of 0.102 M CuCl2?

Verified step by step guidance
1
Identify the balanced chemical equation: \(2 \text{Na}_3\text{PO}_4(aq) + 3 \text{CuCl}_2(aq) \rightarrow \text{Cu}_3(\text{PO}_4)_2(s) + 6 \text{NaCl}(aq)\).
Determine the moles of \(\text{CuCl}_2\) using its concentration and volume: \(\text{moles of } \text{CuCl}_2 = 0.102 \text{ M} \times 0.0954 \text{ L}\).
Use the stoichiometry of the reaction to find the moles of \(\text{Na}_3\text{PO}_4\) needed. According to the balanced equation, 2 moles of \(\text{Na}_3\text{PO}_4\) react with 3 moles of \(\text{CuCl}_2\).
Calculate the moles of \(\text{Na}_3\text{PO}_4\) required using the ratio from the balanced equation: \(\text{moles of } \text{Na}_3\text{PO}_4 = \frac{2}{3} \times \text{moles of } \text{CuCl}_2\).
Determine the volume of \(0.175 \text{ M } \text{Na}_3\text{PO}_4\) solution needed using its concentration: \(\text{Volume} = \frac{\text{moles of } \text{Na}_3\text{PO}_4}{0.175 \text{ M}}\).

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on the balanced chemical equation. It allows us to determine the proportions of substances involved in a reaction, which is essential for solving problems related to the amounts of reactants needed or products formed.
Recommended video:
Guided course
01:16
Stoichiometry Concept

Molarity

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (M) and is crucial for converting between volume and amount of substance in chemical reactions, enabling us to calculate how much of a solution is required to react with a given amount of another substance.
Recommended video:
Guided course
01:13
Molarity

Precipitation Reactions

Precipitation reactions occur when two aqueous solutions react to form an insoluble solid, known as a precipitate. Understanding these reactions is important for predicting the formation of solids in solution and for calculating the amounts of reactants needed to achieve complete precipitation, as seen in the given reaction.
Recommended video:
Guided course
01:53
Selective Precipitation
Related Practice
Textbook Question

What is the molarity of ZnCl2 that forms when 25.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 275 mL. Zn(s) + CuCl2(aq) → ZnCl2(aq) + Cu(s)

2834
views
1
rank
Textbook Question

If 123 mL of a 1.1 M glucose solution is diluted to 500.0 mL, what is the molarity of the diluted solution?

1850
views
Textbook Question

To what volume should you dilute 50.0 mL of a 12 M stock HNO3 solution to obtain a 0.100 M HNO3 solution?

1716
views
Textbook Question

If 3.5 L of a 4.8 M SrCl2 solution is diluted to 45 L, what is the molarity of the diluted solution?

1131
views
Textbook Question

What is the minimum amount of 6.0 M H2SO4 necessary to produce 25.0 g of H2(g) according to the reaction between aluminum and sulfuric acid? 2 Al(s) + 3 H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)

5198
views
4
rank
Textbook Question

Consider the reaction: Li2S(aq) + Co(NO3)2(aq) → 2 LiNO3(aq) + CoS(s) What volume of 0.150 M Li2S solution is required to completely react with 125 mL of 0.150 M Co(NO3)2?

2484
views