Cyclohexane, C6H12, is an important starting material used in the industrial synthesis of nylon. Each carbon has four covalent bonds, two to hydrogen and two to other carbons. Draw the structural formula of cyclohexane.

Video transcript

Everyone in this video being told that cycle octane with a formula of ch H. 16. It is cyclic hydrocarbon formed with the hydrogenation of cycle Octa dying. Each carbon item follows the octet rule being brought to four other atoms provide the structural form A for a cycle octane. So a cyclic hydrocarbon is basically a structure or a structure of just carbons. And hi regions from this cyclone name, that just means that we have a cyclic hydrocarbon. So that's already something that we're being told. So kind of just eliminate that now for the arts part of this. So this is a prefect. So we have O. C. T. Are the same thing as having eight carbons. So this oct here equals to eight carbons and this suffix here of A. And M. Stands for that. We have an al cane which is the same thing as hydrocarbon and we only have single bonds throughout the structure. So a single bond, hydro carbon. Alright so again each carbon is being brought into to hodgins and two carbons to satisfy the octet rule. If we have this eight members ring. So let's start with the structure then. So we have this carbon here carbon here carbon carbon than completing our regular octagon. Carbon here. Carbon here, carbon here carbon here. So let's see if we made the perfect kind of shape here and see if we put the amount the correct amount of carbons. So we have 1234567 and eight. Alright so now that we see you have two different or two bonds connected to each carbon, we need to add two more high regions. So we'll have here one and two, one and two. One and 21 and two. The same exact thing for the rest of the carbons here. Just go around the ring and add in those higher regions because we need to fulfill all the carbons octet rule and all the hydrogen duet role. So this right here is going to be the complete structure of our cyclo octane and this right here is going to be my final answer for this problem. Thank you all so much for watching.