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Ch.19 - Chemical Thermodynamics

Chapter 19, Problem 104

In chemical kinetics, the entropy of activation is the entropy change for the process in which the reactants reach the activated complex. Predict whether the entropy of activation for a bimolecular process is usually positive or negative.

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Hey everyone, we're told that the entropy change for a process that leads to the formation of the activated complex or transition state is known as the entropy of activation, determine whether the sign of the entropy of activation for a biomolecular process would be positive or negative. As we've learned in previous lessons, we know that when the change of entropy is greater than zero, this means our entropy increases now. When our change of entropy is less than zero, this means our entropy decreases. So looking at what they've provided us in our questions them, we were told that we had a by molecular process which is essentially telling us that we have to react INTS. And since they told us that we had the formation of the activated complex or transition state, this is telling us that we have one product. So essentially our reaction was to react ints that ended up forming one product. And as we can see right here, this means our entropy decreases since we have a lesser number of particles. So our final answer here is going to be that the entropy of activation for a biomolecular process would be negative. Now, I hope that made sense. And let us know if you have any questions
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The conversion of natural gas, which is mostly methane, into products that contain two or more carbon atoms, such as ethane (C2H6), is a very important industrial chemical process. In principle, methane can be converted into ethane and hydrogen: 2 CH4(g) → C2H6(g) + H2(g) In practice, this reaction is carried out in the presence of oxygen: 2 CH4(g) + 12 O2(g) → C2H6(g) + H2O(g) (b) Is the difference in ΔG° for the two reactions due primarily to the enthalpy term (ΔH) or the entropy term (-TΔS)?

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Textbook Question

The conversion of natural gas, which is mostly methane, into products that contain two or more carbon atoms, such as ethane (C2H6), is a very important industrial chemical process. In principle, methane can be converted into ethane and hydrogen: 2 CH4(g) → C2H6(g) + H2(g) In practice, this reaction is carried out in the presence of oxygen: 2 CH4(g) + 1/2 O2(g) → C2H6(g) + H2O(g) (c) Explain how the preceding reactions are an example of driving a nonspontaneous reaction, as discussed in the 'Chemistry and Life' box in Section 19.7.

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Textbook Question
Carbon disulfide 1CS22 is a toxic, highly flammable substance. The following thermodynamic data are available for CS21l2 and CS21g2 at 298 K: (e) Use the data in the table to calculate ΔS° at 298 K for the vaporization of CS21l2. Is the sign of ΔS° as you would expect for a vaporization?
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