Factor by any method. See Examples 1–7. 64+(3x+2)3
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Recognize that the expression is a sum of two terms: \$64\( and \)(3x+2)^3\(. Notice that \)64\( is a perfect cube since \)64 = 4^3$.
Rewrite the expression as a sum of cubes: \$4^3 + (3x+2)^3$.
Recall the sum of cubes factoring formula: \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\).
Identify \(a = 4\) and \(b = (3x+2)\), then apply the formula: \((4 + (3x+2)) \left(4^2 - 4(3x+2) + (3x+2)^2\right)\).
Simplify the first factor and expand the terms inside the second factor to write the fully factored form.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Sum of Cubes Formula
The sum of cubes formula states that a³ + b³ = (a + b)(a² - ab + b²). It is used to factor expressions where two terms are each perfect cubes added together. Recognizing the expression as a sum of cubes allows for straightforward factoring.
To apply the sum of cubes formula, each term must be a perfect cube. For example, 64 is 4³, and (3x + 2)³ is already a cube. Recognizing these cubes is essential to rewrite the expression in a form suitable for factoring.
Factoring polynomials involves rewriting expressions as products of simpler polynomials. Techniques include factoring by grouping, special formulas like sum/difference of cubes, and recognizing patterns. Choosing the correct method simplifies solving or further manipulation.