Find one solution for each equation. Assume all angles involved are acute angles. See Example 3. sin(2θ + 10°) = cos(3θ - 20°)
Table of contents
- 0. Review of College Algebra4h 45m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
3. Unit Circle
Defining the Unit Circle
Problem 40
Textbook Question
Find one solution for each equation. Assume all angles involved are acute angles. See Example 3. csc(β + 40°) = sec(β - 20°)
Verified step by step guidance1
Recall the definitions of the cosecant and secant functions: \(\csc \theta = \frac{1}{\sin \theta}\) and \(\sec \theta = \frac{1}{\cos \theta}\). Rewrite the given equation \(\csc(\beta + 40^\circ) = \sec(\beta - 20^\circ)\) as \(\frac{1}{\sin(\beta + 40^\circ)} = \frac{1}{\cos(\beta - 20^\circ)}\).
Cross-multiply to eliminate the fractions, giving \(\cos(\beta - 20^\circ) = \sin(\beta + 40^\circ)\).
Use the co-function identity \(\sin \theta = \cos(90^\circ - \theta)\) to rewrite the right side: \(\sin(\beta + 40^\circ) = \cos(90^\circ - (\beta + 40^\circ)) = \cos(50^\circ - \beta)\).
Set the two cosine expressions equal: \(\cos(\beta - 20^\circ) = \cos(50^\circ - \beta)\). Recall that if \(\cos A = \cos B\), then either \(A = B\) or \(A = 360^\circ - B\) (or in degrees, \(A = B + 360^\circ k\) or \(A = -B + 360^\circ k\) for integer \(k\)). Since angles are acute, focus on the principal solutions.
Solve the equations \(\beta - 20^\circ = 50^\circ - \beta\) and \(\beta - 20^\circ = -(50^\circ - \beta)\) for \(\beta\), then check which solutions are acute angles (between \(0^\circ\) and \(90^\circ\)).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Reciprocal Trigonometric Functions
Cosecant (csc) and secant (sec) are reciprocal functions of sine and cosine, respectively. Specifically, csc(θ) = 1/sin(θ) and sec(θ) = 1/cos(θ). Understanding these relationships allows rewriting the equation in terms of sine and cosine for easier manipulation.
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Introduction to Trigonometric Functions
Trigonometric Equation Solving
Solving trigonometric equations often involves rewriting expressions, using identities, and isolating the variable. Here, equating csc(β + 40°) to sec(β - 20°) requires converting to sine and cosine, then finding β that satisfies the resulting equation within the given domain.
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How to Solve Linear Trigonometric Equations
Domain Restrictions and Acute Angles
The problem specifies that all angles are acute, meaning they lie between 0° and 90°. This restriction limits possible solutions and helps in selecting the correct angle values after solving the equation, ensuring the solution is valid within the given context.
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Finding the Domain of an Equation
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