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Ch 36: Diffraction
Chapter 35, Problem 36

A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from a distant source passing through a slit 0.105 mm wide. At the point in the pattern 3.25° from the center of the central maximum, the total phase difference between wavelets from the top and bottom of the slit is 56.0 rad. (b) What is the intensity at this point, if the intensity at the center of the central maximum is I0?

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First, understand that the intensity distribution in a single-slit diffraction pattern can be described using the formula $I = I_0 \left(\frac{\sin(\beta)}{\beta}\right)^2$, where $\beta = \frac{\pi a \sin(\theta)}{\lambda}$, $I_0$ is the maximum intensity at the center, $a$ is the slit width, $\theta$ is the angle from the central maximum, and $\lambda$ is the wavelength of the light.
Calculate the wavelength $\lambda$ using the given phase difference $\Delta \phi = 56.0 \text{ rad}$ and the relationship $\Delta \phi = \frac{2\pi a \sin(\theta)}{\lambda}$. Rearrange this formula to solve for $\lambda$.
Substitute the value of $\lambda$ back into the expression for $\beta = \frac{\pi a \sin(\theta)}{\lambda}$ to find the value of $\beta$.
Compute the value of $\sin(\beta)/\beta$ using the value of $\beta$ calculated in the previous step.
Finally, substitute the value of $\sin(\beta)/\beta$ into the intensity formula $I = I_0 \left(\frac{\sin(\beta)}{\beta}\right)^2$ to find the relative intensity $I$ at the angle $\theta = 3.25^\circ$ compared to the central maximum intensity $I_0$.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Single-Slit Diffraction

Single-slit diffraction occurs when waves pass through a narrow opening and spread out, creating a pattern of light and dark fringes on a screen. The width of the slit and the wavelength of the light determine the pattern's characteristics, including the angular position of the minima and maxima. This phenomenon illustrates the wave nature of light and is described mathematically by the diffraction formula, which relates the slit width, wavelength, and angle of observation.
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Phase Difference

Phase difference refers to the difference in the phase of two waves at a given point in time and space. In the context of diffraction, it is crucial for determining how waves interfere with each other, leading to constructive or destructive interference. The total phase difference between wavelets from different parts of the slit affects the intensity of the resulting diffraction pattern, with specific angles corresponding to minima and maxima in intensity.
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Intensity of Light

The intensity of light is a measure of the power per unit area carried by a wave, often represented as I. In diffraction patterns, the intensity varies with position due to the interference of light waves. The intensity at any point can be calculated relative to the maximum intensity (I0) at the center of the pattern, using the formula that incorporates the phase difference and the slit width, which helps predict the brightness of the fringes observed.
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Related Practice
Textbook Question
A slit 0.240 mm wide is illuminated by parallel light rays of wavelength 540 nm. The diffraction pattern is observed on a screen that is 3.00 m from the slit. The intensity at the center of the central maximum (u = 0°) is 6.00 x 10^-6 W/m2. (b) What is the intensity at a point on the screen midway between the center of the central maximum and the first minimum?
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Textbook Question
Monochromatic light of wavelength 592 nm from a distant source passes through a slit that is 0.0290 mm wide. In the resulting diffraction pattern, the intensity at the center of the central maximum (u = 0°) is 4.00x10-5 W/m2. What is the intensity at a point on the screen that corresponds to u = 1.20°?
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Textbook Question
A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from a distant source passing through a slit 0.105 mm wide. At the point in the pattern 3.25° from the center of the central maximum, the total phase difference between wavelets from the top and bottom of the slit is 56.0 rad. (a) What is the wavelength of the radiation?
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Textbook Question
Parallel rays of monochromatic light with wavelength 568 nm illuminate two identical slits and produce an interference pattern on a screen that is 75.0 cm from the slits. The centers of the slits are 0.640 mm apart and the width of each slit is 0.434 mm. If the intensity at the center of the central maximum is 5.00x10^-4 W/m2, what is the intensity at a point on the screen that is 0.900 mm from the center of the central maximum?
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Textbook Question
Laser light of wavelength 500.0 nm illuminates two identical slits, producing an interference pattern on a screen 90.0 cm from the slits. The bright bands are 1.00 cm apart, and the third bright bands on either side of the central maximum are missing in the pattern. Find the width and the separation of the two slits.
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Textbook Question

Two satellites at an altitude of 1200 km are separated by 28 km. If they broadcast 3.6-cm microwaves, what minimum receiving-dish diameter is needed to resolve (by Rayleigh’s criterion) the two transmissions?

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