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Ch 36: Diffraction
Chapter 35, Problem 36

A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from a distant source passing through a slit 0.105 mm wide. At the point in the pattern 3.25° from the center of the central maximum, the total phase difference between wavelets from the top and bottom of the slit is 56.0 rad. (a) What is the wavelength of the radiation?

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1
Identify the given values: slit width (a) = 0.105 mm, angle (θ) = 3.25°, and total phase difference (Δφ) = 56.0 rad.
Convert the slit width from millimeters to meters for consistency in SI units.
Understand that the phase difference (Δφ) between wavelets from the top and bottom of the slit can be expressed as Δφ = (2π/λ) * a * sin(θ), where λ is the wavelength of the radiation.
Rearrange the formula to solve for the wavelength λ: λ = (2π * a * sin(θ)) / Δφ.
Substitute the values of a, θ, and Δφ into the rearranged formula to calculate the wavelength λ.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Diffraction

Diffraction is the bending of waves around obstacles and the spreading of waves when they pass through narrow openings. In the context of a single-slit diffraction pattern, it describes how light waves interfere with each other after passing through a slit, leading to a pattern of bright and dark fringes on a screen. The extent of diffraction depends on the wavelength of the light and the width of the slit.
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Phase Difference

Phase difference refers to the difference in the phase of two waves at a given point in time. In diffraction, the phase difference between wavelets emanating from different parts of the slit affects the interference pattern observed. It is crucial for determining the conditions under which constructive or destructive interference occurs, which ultimately shapes the diffraction pattern.
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Wavelength

Wavelength is the distance between successive peaks of a wave and is a fundamental property of electromagnetic radiation. It is directly related to the energy and frequency of the radiation, with shorter wavelengths corresponding to higher energy. In diffraction problems, the wavelength is essential for calculating the positions of the interference fringes and understanding the behavior of light as it interacts with slits.
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Related Practice
Textbook Question
A slit 0.240 mm wide is illuminated by parallel light rays of wavelength 540 nm. The diffraction pattern is observed on a screen that is 3.00 m from the slit. The intensity at the center of the central maximum (u = 0°) is 6.00 x 10^-6 W/m2. (a) What is the distance on the screen from the center of the central maximum to the first minimum?
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Textbook Question
A slit 0.240 mm wide is illuminated by parallel light rays of wavelength 540 nm. The diffraction pattern is observed on a screen that is 3.00 m from the slit. The intensity at the center of the central maximum (u = 0°) is 6.00 x 10^-6 W/m2. (b) What is the intensity at a point on the screen midway between the center of the central maximum and the first minimum?
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Textbook Question
Monochromatic light of wavelength 592 nm from a distant source passes through a slit that is 0.0290 mm wide. In the resulting diffraction pattern, the intensity at the center of the central maximum (u = 0°) is 4.00x10-5 W/m2. What is the intensity at a point on the screen that corresponds to u = 1.20°?
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Textbook Question
A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from a distant source passing through a slit 0.105 mm wide. At the point in the pattern 3.25° from the center of the central maximum, the total phase difference between wavelets from the top and bottom of the slit is 56.0 rad. (b) What is the intensity at this point, if the intensity at the center of the central maximum is I0?
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Textbook Question
Parallel rays of monochromatic light with wavelength 568 nm illuminate two identical slits and produce an interference pattern on a screen that is 75.0 cm from the slits. The centers of the slits are 0.640 mm apart and the width of each slit is 0.434 mm. If the intensity at the center of the central maximum is 5.00x10^-4 W/m2, what is the intensity at a point on the screen that is 0.900 mm from the center of the central maximum?
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Textbook Question
Laser light of wavelength 500.0 nm illuminates two identical slits, producing an interference pattern on a screen 90.0 cm from the slits. The bright bands are 1.00 cm apart, and the third bright bands on either side of the central maximum are missing in the pattern. Find the width and the separation of the two slits.
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