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Ch 34: Geometric Optics
Chapter 34, Problem 34

An object is 16.0 cm to the left of a lens. The lens forms an 36.0 cm to the right of the lens. (c) Draw a principal-ray diagram.

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Identify the type of lens being used. Since the image is formed on the opposite side of the object and is real (as indicated by the positive image distance), the lens is a converging lens.
Locate the object, lens, and image on a horizontal line. Mark the object 16.0 cm to the left of the lens. Since left of the lens is typically considered negative, this is at -16.0 cm.
Mark the image 36.0 cm to the right of the lens. Since right of the lens is considered positive, this is at +36.0 cm.
Draw the principal rays to locate the image accurately: (1) A ray parallel to the principal axis from the object to the lens, which refracts through the focal point on the opposite side. (2) A ray through the center of the lens, which continues in a straight line. (3) A ray through the focal point on the object side, which refracts parallel to the principal axis on the other side.
Verify the ray diagram by ensuring that all refracted rays (or their backward extensions) intersect at the image point, confirming the image location and characteristics (real, inverted, and magnified).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Lens Types

Lenses can be classified into two main types: converging (convex) and diverging (concave). Converging lenses focus parallel rays of light to a point, while diverging lenses spread out light rays. Understanding the type of lens is crucial for predicting how it will manipulate light and form images.
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Thin Lens Equation

Ray Diagrams

Ray diagrams are visual representations used to illustrate how light rays interact with lenses. They typically include principal rays such as the parallel ray, the focal ray, and the central ray. These diagrams help in determining the position, size, and nature (real or virtual) of the image formed by the lens.
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Ray Diagrams for Converging Lenses

Image Formation

Image formation by lenses involves the relationship between object distance, image distance, and focal length, described by the lens formula (1/f = 1/do + 1/di). The nature of the image (real or virtual, upright or inverted) depends on the object's position relative to the lens's focal point. Understanding this relationship is essential for accurately drawing ray diagrams.
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Refraction at Spherical Surfaces
Related Practice
Textbook Question
BIO A person can see clearly up close but cannot focus on objects beyond 75.0 cm. She opts for contact lenses to correct her vision. (a) Is she nearsighted or farsighted?
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Textbook Question
BIO A person can see clearly up close but cannot focus on objects beyond 75.0 cm. She opts for contact lenses to correct her vision. (c) What focal length contact lens is needed, and what is its power in diopters?
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Textbook Question
A thin lens with a focal length of 6.00 cm is used as a simple magnifier. (a) What angular magnification is obtainable with the lens if the object is at the focal point?
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Textbook Question
A Spherical Fish Bowl. A small tropical fish is at the center of a water-filled, spherical fish bowl 28.0 cm in diameter. (a) Find the apparent position and magnification of the fish to an observer outside the bowl. The effect of the thin walls of the bowl may be ignored.
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Textbook Question
The left end of a long glass rod 8.00 cm in diameter, with an index of refraction of 1.60, is ground and polished to a convex hemispherical surface with a radius of 4.00 cm. An object in the form of an arrow 1.50 mm tall, at right angles to the axis of the rod, is located on the axis 24.0 cm to the left of the vertex of the convex surface. Find the position and height of the of the arrow formed by paraxial rays incident on the convex surface. Is the erect or inverted?
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Textbook Question
A lens forms an of an object. The object is 16.0 cm from the lens. The is 12.0 cm from the lens on the same side as the object. (a) What is the focal length of the lens? Is the lens converging or diverging?
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