At the instant when the current in an inductor is increasing at a rate of 0.0640 A/s, the magnitude of the self-induced emf is 0.0160 V. (a) What is the inductance of the inductor?

Video transcript

Welcome back, everybody. We are making observations about a circuit and we are told that the current increases at a rate of 0.52 amps per second were also told that the self induced E M F of the circuit is 0.23 volts. And we are tasked with finding what the induct ear's inducted is inside of the current. We know that the induced E M F is simply just the induct ints times that rate of change for the current. So I'm actually going to divide both sides here by that rate of change for the current. And you'll see here that these terms cancel out on the right leaving us with that are inducted is equal to the induced E M F divided by that rate of change. So let's go ahead and plug in our values here and then we will get our final answer. So we have that are induced E M F is 0.23 divided by our rate of change of 0.52, giving us a final answer of 0.442 Hertz for the induct, its corresponding to our answer choice of D. Thank you all. So much for watching. Hope this video helped. We will see you all in the next one.