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Ch 30: Inductance

Chapter 30, Problem 30

An L-R-C series circuit has L = 0.450 H, C = 2.50 * 10^-5 F, and resistance R. (a) What is the angular frequency of the circuit when R = 0?

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Welcome back, everybody. We are making observations about an L R C circuit and we are told that it is constructed with an induct er that has an induct inside of 550 mil hearts, a capacitor with capacitance of 5500.48 micro fare adds and a resistor with some resistance R. And we are tasked with finding what the angular frequency is going to be once we replace the resistor with a low resistance wire, therefore making the resistance negligible. So here's what we can do to make this pretty easy. What we can do is now we can just treat this circuit. I'm sorry here, this is meant to be an L for conductance. We can just treat this as an L C circuit. Now that resistance is negligible. And the formula for angular frequency of an L C circuits is simply just one over the square root of our conductance, tightens our capacities. Let's go ahead and plug in our values here. We have one divided by the square root of 550 times 10 to the negative third because we need hurts and 100.48 times 10 to the negative six because we need fair ads which when you plug all of this in your calculator gives us an angular frequency of 1.95 times 10 to the third radiance per second corresponding to answer choice B Thank you all so much for watching this. For your help. See you all in the next one.