The power of a certain CD player operating at 120 V rms is 20.0 W. Assuming that the CD player behaves like a pure resistor, find (a) the maximum instantaneous power.

Video transcript

Hi, everyone in this practice problem, we're being asked to calculate the maximum instantaneous power or pre max dissipated in a resistor. We'll have an electric water resistor heater connected across a 244 Pr MS potential difference. The water heater consumes on average 1000 and 500 watt. And we're being asked to calculate the maximum instantaneous power or P max dissipated in the resistor. The options given are a 2000 watt B 2500 watt C 3000 watt or lastly D we will not be able to determine from the given information. So the power curve for a pure resistor is symmetric about a value pavpav equal to one half of its maximum value of E I. So in this case, Pav will equals to half of P max rearranging this, we will then get P max to then equals to two times PAV. And we are given the PAV or the cons uh the power consumed on average by the water heater to be 1500 watt. So let's substitute that into our equation. So P max will then equals to two multiplied by 1500.0 watt which will then give us our P max value to then be 3000.0 watt. So the maximum instantaneous power P max dissipated in the resistor is going to equal to 3000 watt which will correspond to option C in our answer choices. So option C will be the answer to this video and that will be it for this one. If you guys still have any sort of confusion, please make sure to check out our other lesson videos on similar topic. That'll be it for this video. Thank you.