Skip to main content
Ch 27: Magnetic Field and Magnetic Forces

Chapter 27, Problem 27

A particle with mass 1.81x10^-3 kg and a charge of 1.22x10^-8 C has, at a given instant, a velocity v=(3.00x10^4 m>s)j. What are the magnitude and direction of the particle's acceleration produced by a uniform magnetic field B=(1.63 T)i+(0.980 T)j?

Verified Solution
Video duration:
4m
This video solution was recommended by our tutors as helpful for the problem above.
1805
views
Was this helpful?

Video transcript

Hey everyone. So this problem is working with magnetic forces. Let's see what they're giving us. And what they're asking for us, we have masks of alpha particles that's given and a given charge the alpha particle that is emitted by a radioactive substance moves into the region of a uniform magnetic field of a given magnitude and direction. So a vector field at any given moment, the alpha particle has a velocity that is also given to us. And we are asked to find the magnitude and direction of its acceleration vector at this moment where the velocity was measured. So the first thing we can do is recall that the magnitude of the force is given by Q be cross be where Q is our charge V is our velocity and B is our magnetic field. So from there, let's look at the term. So from the problem, so Q we are given its 3.20 times 10 to the minus 19 columns are speed was also given and that's 12 times 10 to the four m per second. And that is in our positive I direction positive X and then our magnetic field magnitude B is given in vector for as to Tesla's in the I direction. And then again, a positive 3.2 Tesla in the J Direction. So when we plug that in, and for each of these terms here and solve, We are left with a force of 1.2, 3 times 10 to the - newtons in the K direction. They're not asking us for the force though, they're asking us for, it's the magnitude and direction of the acceleration vector. Luckily, we can recall Newton's second law F equals M A and use that to solve for the acceleration. So the mass was also given to us in this problem As 6. times 10 to the -27 kg. And so we can rewrite this to solve for acceleration. It's going to be divided by the mass we've solved for the force vector 1.2, 3 times 10 to the -13 Newtons positive K direction. And then the mass is 6.64 times -27 kg. And that gives us 1.8, 5 times 10 to the m per second squared. And we are still in the positive K direction. So let's look at our possible answer choices. And so that aligns with choice, see we have 1.85 times 10 to the 13 m per second squared and the acceleration is in the positive Z direction. So positive K is the same as positive Z um And that's all we have for this problem. The correct answer is choice seed. All right. We'll see you in the next video.
Related Practice
Textbook Question
A long wire carrying 4.50 A of current makes two 90° bends, as shown in Fig. E27.35

. The bent part of the wire passes through a uniform 0.240-T magnetic field directed as shown in the figure and confined to a limited region of space. Find the magnitude and direction of the force that the magnetic field exerts on the wire.
2831
views
Textbook Question
A thin, 50.0-cm-long metal bar with mass 750 g rests on, but is not attached to, two metallic supports in a uniform 0.450-T magnetic field, as shown in Fig. E27.37 . A battery and a 25.0-ohm resistor in series are connected to the supports. (a) What is the highest voltage the battery can have without breaking the circuit at the supports? (b) The battery voltage has the maximum value calculated in part (a). If the resistor suddenly gets partially short-circuited, decreasing its resistance to 2.00-ohm, find the initial acceleration of the bar.
950
views
2
rank
Textbook Question
A straight, vertical wire carries a current of 2.60 A downward in a region between the poles of a large superconducting electromagnet, where the magnetic field has magnitude B = 0.588 T and is horizontal. What are the magnitude and direction of the magnetic force on a 1.00-cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is (a) east?

1224
views
Textbook Question
An electron experiences a magnetic force of magnitude 4.60x10^-15 N when moving at an angle of 60.0° with respect to a magnetic field of magnitude 3.50x10^-3 T. Find the speed of the electron.
840
views
Textbook Question
A flat, square surface with side length 3.40 cm is in the xy-plane at z = 0. Calculate the magnitude of the flux through this surface produced by a magnetic field B=(0.200 T)i+(0.300 T)j-(0.500 T)k .
1222
views
Textbook Question
A circular area with a radius of 6.50 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B = 0.230 T (b) at an angle of 53.1° from the +z-direction?
1000
views