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Ch 19: The First Law of Thermodynamics
Chapter 19, Problem 19

Two moles of an ideal gas are heated at constant pressure from T = 27°C to T = 107°C. (b) Calculate the work done by the gas

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1
Convert the initial and final temperatures from Celsius to Kelvin by adding 273.15 to each. This gives you T1 = 300.15 K and T2 = 380.15 K.
Use the formula for work done by an ideal gas at constant pressure, which is W = P \\Delta V, where P is the pressure and \\Delta V is the change in volume.
To find \\Delta V, use the ideal gas law rearranged to V = \frac{nRT}{P}. Calculate V1 using T1 and V2 using T2, keeping n (number of moles), R (ideal gas constant), and P (pressure) constant.
Subtract V1 from V2 to find \\Delta V.
Substitute P and \\Delta V into the formula for work done to find W.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Ideal Gas Law

The Ideal Gas Law relates the pressure, volume, temperature, and number of moles of an ideal gas through the equation PV = nRT. This law is fundamental in understanding the behavior of gases under various conditions, allowing us to predict how changes in temperature and pressure affect volume and vice versa.
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Work Done by a Gas

In thermodynamics, the work done by a gas during expansion or compression at constant pressure is calculated using the formula W = PΔV, where W is work, P is pressure, and ΔV is the change in volume. This concept is crucial for determining how much energy is transferred when the gas expands or contracts.
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Constant Pressure Process

A constant pressure process occurs when a gas expands or contracts while maintaining a constant pressure. In such processes, the heat added to the system results in work done by the gas, which can be calculated using the specific heat capacity at constant pressure, making it essential for solving problems involving heating gases.
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Related Practice
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Textbook Question
An experimenter adds 970 J of heat to 1.75 mol of an ideal gas to heat it from 10.0°C to 25.0°C at constant pressure. The gas does +223 J of work during the expansion. (b) Calculate γ for the gas.
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Textbook Question
CALC The temperature of 0.150 mol of an ideal gas is held constant at 77.0°C while its volume is reduced to 25.0% of its initial volume. The initial pressure of the gas is 1.25 atm. (c) Does the gas exchange heat with its surroundings? If so, how much? Does the gas absorb or liberate heat?
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Textbook Question
A gas undergoes two processes. In the first, the volume remains constant at 0.200 m^3 and the pressure increases from 2.00 * 10^5 Pa to 5.00 * 10^5 Pa. The second process is a compression to a volume of 0.120 m^3 at a constant pressure of 5.00 * 10^5 Pa. (b) Find the total work done by the gas during both processes.
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Textbook Question
Two moles of an ideal gas are heated at constant pressure from T = 27°C to T = 107°C. (a) Draw a pV-diagram for this process. (ANSWER IS )
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Textbook Question
A gas undergoes two processes. In the first, the volume remains constant at 0.200 m^3 and the pressure increases from 2.00 * 10^5 Pa to 5.00 * 10^5 Pa. The second process is a compression to a volume of 0.120 m^3 at a constant pressure of 5.00 * 10^5 Pa. (a) In a pV-diagram, show both processes.
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