Skip to main content
Ch 19: The First Law of Thermodynamics
Chapter 19, Problem 19

Boiling Water at High Pressure. When water is boiled at a pressure of 2.00 atm, the heat of vaporization is 2.20 * 10^6 J/kg and the boiling point is 120°C. At this pressure, 1.00 kg of water has a volume of 1.00 * 10^-3 m^3 , and 1.00 kg of steam has a volume of 0.824 m^3. (a) Compute the work done when 1.00 kg of steam is formed at this temperature.

Verified step by step guidance
1
Identify the initial and final volumes of the water and steam. The initial volume when water is in liquid form is 1.00 * 10^-3 m^3, and the final volume when it turns into steam is 0.824 m^3.
Calculate the change in volume, \( \Delta V \), which is the final volume minus the initial volume. Use the formula: \( \Delta V = V_{final} - V_{initial} \).
Use the formula for work done during a constant pressure process, which is given by \( W = P \Delta V \), where \( P \) is the pressure and \( \Delta V \) is the change in volume.
Substitute the values into the formula: \( P = 2.00 \, \text{atm} \) (convert this to Pascals if necessary using the conversion 1 atm = 101325 Pa) and the \( \Delta V \) calculated in step 2.
Calculate the work done, which will be in Joules, using the substituted values.

Verified Solution

Video duration:
5m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Heat of Vaporization

The heat of vaporization is the amount of energy required to convert a unit mass of a substance from liquid to gas at constant temperature and pressure. For water, this value is significant because it determines how much energy must be supplied to boil water. In this case, the heat of vaporization is given as 2.20 * 10^6 J/kg, indicating the energy needed to convert 1 kg of water into steam at 2.00 atm.
Recommended video:
Guided course
05:
Finding Amount of Water Vaporized

Work Done in Phase Change

When a substance undergoes a phase change, such as from liquid to gas, work can be done on or by the system due to changes in volume. The work done during the formation of steam can be calculated using the formula W = PΔV, where P is the pressure and ΔV is the change in volume. In this scenario, the volume of steam is significantly larger than that of water, leading to positive work done by the system as it expands.
Recommended video:
Guided course
10:40
Latent Heat & Phase Changes

Ideal Gas Law and Phase Behavior

The Ideal Gas Law (PV = nRT) describes the behavior of gases under various conditions of pressure, volume, and temperature. Although steam behaves like an ideal gas under certain conditions, it is important to consider the phase behavior of water at high pressures. The boiling point of water increases with pressure, as indicated by the boiling point of 120°C at 2.00 atm, which affects the calculations of work and energy during the phase transition.
Recommended video:
Guided course
07:21
Ideal Gases and the Ideal Gas Law
Related Practice
Textbook Question
A cylinder contains 0.0100 mol of helium at T = 27.0°C. (a) How much heat is needed to raise the temperature to 67.0°C while keeping the volume constant? Draw a pV-diagram for this process. (b) If instead the pressure of the helium is kept constant, how much heat is needed to raise the temperature from 27.0°C to 67.0°C? Draw a pV-diagram for this process. (c) What accounts for the difference between your answers to parts (a) and (b)? In which case is more heat required? What becomes of the additional heat? (d) If the gas is ideal, what is the change in its internal energy in part (a)? In part (b)? How do the two answers compare? Why?
389
views
Textbook Question
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. The initial temperature of the gas is 27.0°C and the pressure is constant. As part of a machine design project, calculate the final temperature of the gas after it has done 2.40 * 10^3 J of work.
1149
views
2
rank
Textbook Question
A gas in a cylinder expands from a volume of 0.110 m^3 to 0.320 m^3 . Heat flows into the gas just rapidly enough to keep the pressure constant at 1.65 * 10^5 Pa during the expansion. The total heat added is 1.15 * 10^5 J. (a) Find the work done by the gas.
530
views
Textbook Question
Heat Q flows into a monatomic ideal gas, and the volume increases while the pressure is kept constant. What fraction of the heat energy is used to do the expansion work of the gas?
643
views
Textbook Question
Propane gas (C3H8) behaves like an ideal gas with g = 1.127. Determine the molar heat capacity at constant volume and the molar heat capacity at constant pressure
1216
views
Textbook Question
During an isothermal compression of an ideal gas, 410 J of heat must be removed from the gas to maintain constant temperature. How much work is done by the gas during the process?
1176
views