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Ch 12: Fluid Mechanics
Chapter 12, Problem 12

Home Repair. You need to extend a 2.50-inch-diameter pipe, but you have only a 1.00-inch-diameter pipe on hand. You make a fitting to connect these pipes end to end. If the water is flowing at 6.00 cm/s in the wide pipe, how fast will it be flowing through the narrow one?

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1
Identify the diameters of the two pipes and convert them into consistent units if necessary. In this case, convert the diameters from inches to centimeters: 2.50 inches is approximately 6.35 cm and 1.00 inch is approximately 2.54 cm.
Use the formula for the area of a circle, \(A = \pi r^2\), to calculate the cross-sectional areas of both pipes. Remember to first calculate the radius of each pipe by dividing the diameter by 2.
Apply the principle of conservation of mass, which implies that the mass flow rate must be constant throughout the pipe system. This can be expressed as \(A_1 v_1 = A_2 v_2\), where \(A_1\) and \(A_2\) are the cross-sectional areas of the wide and narrow pipes, respectively, and \(v_1\) and \(v_2\) are the flow velocities in these pipes.
Substitute the known values into the equation from step 3. You know the flow velocity in the wide pipe (\(v_1\)) and the areas of both pipes (\(A_1\) and \(A_2\)) calculated in step 2.
Solve the equation for \(v_2\), the flow velocity in the narrow pipe, to find how fast the water will be flowing through it.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Continuity Equation

The Continuity Equation states that for an incompressible fluid flowing through a pipe, the product of the cross-sectional area and the fluid velocity must remain constant. This principle can be expressed as A1V1 = A2V2, where A is the area and V is the velocity. It implies that if the diameter of the pipe decreases, the velocity of the fluid must increase to maintain the same flow rate.
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Cross-Sectional Area

The cross-sectional area of a pipe is the area of a slice taken perpendicular to the flow direction. For a circular pipe, it can be calculated using the formula A = π(d/2)², where d is the diameter. Understanding the cross-sectional area is crucial for applying the Continuity Equation, as it directly influences the velocity of the fluid in different sections of the pipe.
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Fluid Dynamics

Fluid dynamics is the study of the behavior of fluids in motion. It encompasses various principles, including the effects of pressure, velocity, and flow rate. In this context, understanding fluid dynamics helps explain how changes in pipe diameter affect the speed of water flow, which is essential for solving the problem of connecting pipes of different sizes.
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Related Practice
Textbook Question
A cube 5.0 cm on each side is made of a metal alloy. After you drill a cylindrical hole 2.0 cm in diameter all the way through and perpendicular to one face, you find that the cube weighs 6.30 N. (a) What is the density of this metal?
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Textbook Question
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Textbook Question
BIO In intravenous feeding, a needle is inserted in a vein in the patient's arm and a tube leads from the needle to a reservoir of fluid (density 1050 kg/m^3) located at height h above the arm. The top of the reservoir is open to the air. If the gauge pressure inside the vein is 5980 Pa, what is the minimum value of h that allows fluid to enter the vein? Assume the needle diameter is large enough that you can ignore the viscosity of the liquid.
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You are designing a diving bell to withstand the pressure of seawater at a depth of 250 m. (a) What is the gauge pressure at this depth? (You can ignore changes in the density of the water with depth.) (b) At this depth, what is the net force due to the water outside and the air inside the bell on a circular glass window 30.0 cm in diameter if the pressure inside the diving bell equals the pressure at the surface of the water? (Ignore the small variation of pressure over the surface of the window.)
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Textbook Question
You are designing a diving bell to withstand the pressure of seawater at a depth of 250 m. (a) What is the gauge pressure at this depth? (You can ignore changes in the density of the water with depth.) (b) At this depth, what is the net force due to the water outside and the air inside the bell on a circular glass window 30.0 cm in diameter if the pressure inside the diving bell equals the pressure at the surface of the water? (Ignore the small variation of pressure over the surface of the window.)
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