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Ch 12: Fluid Mechanics
Chapter 12, Problem 12

BIO In intravenous feeding, a needle is inserted in a vein in the patient's arm and a tube leads from the needle to a reservoir of fluid (density 1050 kg/m^3) located at height h above the arm. The top of the reservoir is open to the air. If the gauge pressure inside the vein is 5980 Pa, what is the minimum value of h that allows fluid to enter the vein? Assume the needle diameter is large enough that you can ignore the viscosity of the liquid.

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1
Identify the relevant pressures involved in the problem. The gauge pressure in the vein is given as 5980 Pa, and the atmospheric pressure acts on the top of the fluid in the reservoir.
Understand that the fluid will flow into the vein if the hydrostatic pressure at the needle, due to the fluid column of height h, exceeds the gauge pressure in the vein.
Use the hydrostatic pressure formula to calculate the pressure at the bottom of the fluid column: \( P = \rho g h \), where \( \rho \) is the density of the fluid, \( g \) is the acceleration due to gravity (approximately 9.81 m/s^2), and \( h \) is the height of the fluid column.
Set up the equation to find the minimum height h by equating the hydrostatic pressure to the gauge pressure in the vein. The equation will be \( \rho g h = 5980 \, \text{Pa} \).
Solve for h by rearranging the equation: \( h = \frac{5980}{\rho g} \). Substitute the values of \( \rho \) and \( g \) to find the minimum height.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hydrostatic Pressure

Hydrostatic pressure is the pressure exerted by a fluid at equilibrium due to the force of gravity. It increases with depth in a fluid and is given by the formula P = ρgh, where P is the pressure, ρ is the fluid density, g is the acceleration due to gravity, and h is the height of the fluid column. In this context, it helps determine how high the fluid reservoir must be to overcome the pressure in the vein.
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Gauge Pressure

Gauge pressure is the pressure relative to atmospheric pressure, meaning it measures the pressure of a fluid above the ambient atmospheric pressure. In this scenario, the gauge pressure of 5980 Pa indicates the pressure inside the vein that must be overcome by the hydrostatic pressure from the fluid reservoir to allow fluid to flow into the vein.
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Fluid Dynamics

Fluid dynamics is the study of the behavior of fluids in motion and the forces acting on them. In this problem, it is essential to understand how the pressure difference between the fluid in the reservoir and the pressure in the vein influences the flow of fluid. The principles of fluid dynamics help explain how the height of the fluid reservoir affects the ability of the fluid to enter the vein.
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Related Practice
Textbook Question
A shower head has 20 circular openings, each with radius 1.0 mm. The shower head is connected to a pipe with radius 0.80 cm. If the speed of water in the pipe is 3.0 m/s, what is its speed as it exits the shower-head openings?
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A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355-L cans per minute. At point 2 in the pipe, the gauge pressure is 152 kPa and the cross-sectional area is 8.00 cm^2. At point 1, 1.35 m above point 2, the cross-sectional area is 2.00 cm^2. Find the (b) volume flow rate. (c) flow speeds at points 1 and 2.
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Textbook Question
Home Repair. You need to extend a 2.50-inch-diameter pipe, but you have only a 1.00-inch-diameter pipe on hand. You make a fitting to connect these pipes end to end. If the water is flowing at 6.00 cm/s in the wide pipe, how fast will it be flowing through the narrow one?
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Textbook Question
You are designing a diving bell to withstand the pressure of seawater at a depth of 250 m. (a) What is the gauge pressure at this depth? (You can ignore changes in the density of the water with depth.) (b) At this depth, what is the net force due to the water outside and the air inside the bell on a circular glass window 30.0 cm in diameter if the pressure inside the diving bell equals the pressure at the surface of the water? (Ignore the small variation of pressure over the surface of the window.)
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Textbook Question
You are designing a diving bell to withstand the pressure of seawater at a depth of 250 m. (a) What is the gauge pressure at this depth? (You can ignore changes in the density of the water with depth.) (b) At this depth, what is the net force due to the water outside and the air inside the bell on a circular glass window 30.0 cm in diameter if the pressure inside the diving bell equals the pressure at the surface of the water? (Ignore the small variation of pressure over the surface of the window.)
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Textbook Question
BIO. There is a maximum depth at which a diver can breathe through a snorkel tube (Fig. E12.17) because as the depth increases, so does the pressure difference, which tends to collapse the diver's lungs. Since the snorkel connects the air in the lungs to the atmosphere at the surface, the pressure inside the lungs is atmospheric pressure. What is the external– internal pressure difference when the diver's lungs are at a depth of 6.1 m (about 20 ft)? Assume that the diver is in fresh-water. (A scuba diver breathing from compressed air tanks can operate at greater depths than can a snorkeler, since the pressure of the air inside the scuba diver's lungs increases to match the external pressure of the water.)

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