A brass wire is to withstand a tensile force of 350 N without breaking. What minimum diameter must the wire have?

Video transcript

Welcome back everybody. We are taking a look at a steel cable and we are told that it can support some maximum tension, which I'm going to represent by by by this variable. Here we're told that the breaking stress of our cable is five times 10 to the eighth pascal's and we are told that the diameter of the cable is three centimeters or 30.3 m. And we are tasked with finding what this maximum stress is. Well, we know that the breaking stress is equal to the maximum tension divided by the area of the cable. Right? Multiplying by area on both sides. We get that our desired value is just equal to breaking stress times the area of the cable. So let's go ahead and plug in those values we have that our maximum tension is equal to our breaking stress of five times 10 to the eighth pascal's times are area of a cable. So cross section is just a circle that we are going to have. Let's see here. Hi, Times are diameter divided by two because we need the radius squared, which when you plug all of this interior calculator, you get that. The maximum attention it can support is 3.5 times 10 to the fifth. Newtons corresponding to answer choice. A thank you all so much for watching. Hope this video helped. We will see you all in the next one