Skip to main content
Ch 09: Rotation of Rigid Bodies
Chapter 9, Problem 9

Find the moment of inertia of a hoop (a thin-walled, hollow ring) with mass M and radius R about an axis perpendicular to the hoop's plane at an edge.

Verified step by step guidance
1
Identify the given parameters: mass of the hoop (M) and radius (R).
Recognize that the moment of inertia for a hoop about an axis through its center perpendicular to its plane is given by the formula $I_{center} = MR^2$.
Apply the parallel axis theorem to find the moment of inertia about an axis at the edge of the hoop. The parallel axis theorem states that $I = I_{center} + Md^2$, where $d$ is the distance from the new axis to the original axis through the center.
Since the axis is now at the edge of the hoop, the distance $d$ from the center of the hoop to the edge is equal to the radius of the hoop, $R$.
Substitute $d = R$ into the parallel axis theorem formula to get $I = MR^2 + MR^2 = 2MR^2$.

Verified Solution

Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Moment of Inertia

The moment of inertia is a measure of an object's resistance to rotational motion about a specific axis. It depends on the mass distribution relative to that axis. For a hoop, the moment of inertia can be calculated using the formula I = Σ(m * r²), where m is the mass of the particles and r is their distance from the axis of rotation.
Recommended video:
Guided course
11:47
Intro to Moment of Inertia

Parallel Axis Theorem

The parallel axis theorem allows us to find the moment of inertia of an object about any axis parallel to an axis through its center of mass. It states that I = I_cm + Md², where I_cm is the moment of inertia about the center of mass, M is the mass of the object, and d is the distance between the two axes. This theorem is essential for calculating the moment of inertia of the hoop about an edge.
Recommended video:
Guided course
13:46
Parallel Axis Theorem

Thin-Walled Hoop

A thin-walled hoop is a hollow circular object with negligible thickness compared to its radius. Its mass is uniformly distributed along its circumference. The moment of inertia for a thin-walled hoop about an axis through its center is given by I = MR². However, when calculating for an edge, the parallel axis theorem must be applied to adjust this value.
Recommended video:
07:58
Thin Lens Equation
Related Practice
Textbook Question
A compound disk of outside diameter 140.0 cm is made up of a uniform solid disk of radius 50.0 cm and area density 3.00 g/cm^2 surrounded by a concentric ring of inner radius 50.0 cm, outer radius 70.0 cm, and area density 2.00 g^cm^2. Find the moment of inertia of this object about an axis perpendicular to the plane of the object and passing through its center.
933
views
Textbook Question
A uniform bar has two small balls glued to its ends. The bar is 2.00 m long and has mass 4.00 kg, while the balls each have mass 0.300 kg and can be treated as point masses. Find the moment of inertia of this combination about an axis (d) parallel to the bar and 0.500 m from it.
707
views
Textbook Question
A thin, rectangular sheet of metal has mass M and sides of length a and b. Use the parallel-axis theorem to calculate the moment of inertia of the sheet for an axis that is perpendicular to the plane of the sheet and that passes through one corner of the sheet.
1722
views
Textbook Question
Compact Disc. A compact disc (CD) stores music in a coded pattern of tiny pits 10^-7 m deep. The pits are arranged in a track that spirals outward toward the rim of the disc; the inner and outer radii of this spiral are 25.0 mm and 58.0 mm, respectively. As the disc spins inside a CD player, the track is scanned at a constant linear speed of 1.25 m/s. (b) The maximum playing time of a CD is 74.0 min. What would be the length of the track on such a maximum-duration CD if it were stretched out in a straight line?
1130
views
Textbook Question
Compact Disc. A compact disc (CD) stores music in a coded pattern of tiny pits 10^-7 m deep. The pits are arranged in a track that spirals outward toward the rim of the disc; the inner and outer radii of this spiral are 25.0 mm and 58.0 mm, respectively. As the disc spins inside a CD player, the track is scanned at a constant linear speed of 1.25 m/s. (c) What is the average angular acceleration of a maximumduration CD during its 74.0-min playing time? Take the direction of rotation of the disc to be positive.
434
views
Textbook Question
A wheel is turning about an axis through its center with constant angular acceleration. Starting from rest, at t = 0, the wheel turns through 8.20 revolutions in 12.0 s. At t = 12.0 s the kinetic energy of the wheel is 36.0 J. For an axis through its center, what is the moment of inertia of the wheel?
1288
views