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Ch 05: Applying Newton's Laws

Chapter 5, Problem 5

The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which can function as a second hand (so that it makes one revolution every 60.0 s).(c) What would be the time for one revolution if the passenger's apparent weight at the highest point were zero?

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Welcome back everybody. We have some objects that is tied to a rope and we are going to sting this object around along this circular path. Right here, we're told a couple of different things. We are told that the mass of this object is five kg and that the radius of this circular path is two m. We are also told that the tension at the top of our point is equal to zero. So what does this mean here for us? Well, it means that the weight of our object is equal to the centripetal force when we are spinning this object, meaning that the acceleration due to gravity is equal to our radial acceleration. Now we are tasked with finding what the period is of our revolution. Well, the formula for a period is two pi times the radius over our tangential velocity. But what is our tangential velocity. But we also know from centripetal equations that are radial acceleration is equal to our tangential velocity over are multiplying both sides by our. Here we get that our tangential velocity equal to the square root of our radial acceleration, which we've already established is equal to Earth's acceleration due to gravity times our radius. Let's go ahead and plug in some values so that we can go ahead and find our period of revolution here. Our tangential velocity is equal to the square root of Earth's acceleration due to gravity 9.8 times our radius, which is two. Which when you plug this into your calculator, you get that our velocity is 4.43 m per second. Plugging this into our equation for our period, we get that T. Is equal to two pi times the radius of two, divided by 4.43, Giving us our final answer of 2. seconds corresponding to answer choice. C. Thank you guys so much for watching. Hope this video helped. We will see you all in the next one.
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Textbook Question
A small remote-controlled car with mass 1.60 kg moves at a constant speed of υ = 12.0 m/s in a track formed by a vertical circle inside a hollow metal cylinder that has a radius of 5.00 m (Fig. E5.45). What is the magnitude of the normal force exerted on the car by the walls of the cylinder at (b) point B (top of the track)?

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Textbook Question
A small car with mass 0.800 kg travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m (Fig. E5.45). If the normal force exerted by the track on the car when it is at the top of the track (point B) is 6.00 N, what is the normal force on the car when it is at the bottom of the track (point A)?
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Textbook Question
The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which can function as a second hand (so that it makes one revolution every 60.0 s). (b) A passenger weighs 882 N at the weight-guessing booth on the ground. What is his apparent weight at the highest and at the lowest point on the Ferris wheel?
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Textbook Question
The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which can function as a second hand (so that it makes one revolution every 60.0 s). (d) What then would be the passenger's apparent weight at the lowest point?
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Textbook Question
flat (unbanked) curve on a highway has a radius of 170.0 m. A car rounds the curve at a speed of 25.0 m/s. (a) What is the minimum coefficient of static friction that will prevent sliding?
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Textbook Question
You throw a baseball straight upward. The drag force is proportional to υ2. In terms of g, what is the y-component of the ball's acceleration when the ball's speed is half its terminal speed and (a) it is moving up?
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