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Ch 03: Motion in Two or Three Dimensions
Chapter 3, Problem 3

At its Ames Research Center, NASA uses its large '20-G' centrifuge to test the effects of very large accelerations ('hypergravity') on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge's arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. (a) How fast must the astronaut's head be moving to experience this maximum acceleration?

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Identify the given values: the length of the centrifuge arm (radius, r) is 8.84 m, and the maximum acceleration (a) is 12.5 times the acceleration due to gravity (g = 9.8 m/s^2).
Calculate the maximum acceleration in meters per second squared by multiplying 12.5g by the acceleration due to gravity (g).
Use the formula for centripetal acceleration, \( a = \frac{v^2}{r} \), where \( v \) is the linear speed of the astronaut's head and \( r \) is the radius of the motion (length of the arm).
Rearrange the formula to solve for \( v \): \( v = \sqrt{a \cdot r} \).
Substitute the values of \( a \) and \( r \) into the equation to find the speed \( v \) of the astronaut's head.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Centripetal Acceleration

Centripetal acceleration is the acceleration directed towards the center of a circular path that an object follows. It is necessary for maintaining circular motion and is calculated using the formula a = v²/r, where 'a' is the centripetal acceleration, 'v' is the tangential speed, and 'r' is the radius of the circular path. In the context of the centrifuge, this acceleration is what the astronaut experiences as they are spun around.
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Gravitational Force and g-Forces

The term 'g-force' refers to the force of gravity on an object, expressed in multiples of the acceleration due to Earth's gravity (approximately 9.81 m/s²). When an astronaut experiences 12.5g, it means they feel an acceleration equivalent to 12.5 times that of Earth's gravity. This concept is crucial for understanding the physical stresses placed on the body during high acceleration scenarios, such as those experienced in a centrifuge.
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Tangential Speed

Tangential speed is the linear speed of an object moving along a circular path and is directly related to the radius of the circle and the angular velocity. It can be calculated using the formula v = ωr, where 'v' is the tangential speed, 'ω' is the angular velocity in radians per second, and 'r' is the radius. In the case of the centrifuge, determining the tangential speed at which the astronaut's head must move to achieve the desired acceleration is essential for understanding the dynamics of the system.
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Related Practice
Textbook Question
The earth has a radius of 6380 km and turns around once on its axis in 24 h. (b) If arad at the equator is greater than g, objects will fly off the earth's surface and into space. (We will see the reason for this in Chapter 5.) What would the period of the earth's rotation have to be for this to occur?
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Textbook Question
A model of a helicopter rotor has four blades, each 3.40 m long from the central shaft to the blade tip. The model is rotated in a wind tunnel at 550 rev/min. (a) What is the linear speed of the blade tip, in m/s?
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Textbook Question
A model of a helicopter rotor has four blades, each 3.40 m long from the central shaft to the blade tip. The model is rotated in a wind tunnel at 550 rev/min. (b) What is the radial acceleration of the blade tip expressed as a multiple of g?
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Textbook Question
The coordinates of a bird flying in the xy-plane are given by x(t) = αt and y(t) = 3.0 m − βt2, where α = 2.4 m/s and β = 1.2 m/s2. (c) Calculate the magnitude and direction of the bird's velocity and acceleration at t = 2.0 s.
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Textbook Question
A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by v = [5.00 m/s − (0.0180 m/s3)t2]î + [2.00 m/s + (0.550 m/s2)t]ĵ. (b) What are the magnitude and direction of the car's velocity at t = 8.00 s? (b) What are the magnitude and direction of the car's acceleration at t = 8.00 s?
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Textbook Question
A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 20.0 m/s. A 1.0-kg stone is thrown from the basket with an initial velocity of 15.0 m/s perpendicular to the path of the descending balloon, as measured relative to a person at rest in the basket. That person sees the stone hit the ground 5.00 s after it was thrown. Assume that the balloon continues its downward descent with the same constant speed of 20.0 m/s. (a) How high is the balloon when the rock is thrown?
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