Skip to main content
Ch 03: Motion in Two or Three Dimensions

Chapter 3, Problem 3

A model of a helicopter rotor has four blades, each 3.40 m long from the central shaft to the blade tip. The model is rotated in a wind tunnel at 550 rev/min. (b) What is the radial acceleration of the blade tip expressed as a multiple of g?

Verified Solution
Video duration:
3m
This video solution was recommended by our tutors as helpful for the problem above.
658
views
Was this helpful?

Video transcript

Welcome back everybody. We are making observations about a ceiling fan and we are told that the ceiling fan has a radius of rotation of 60 cm and or .6 m. Now we are told that it also rotates. Its rotations per minute is At full speed. Now we have a little particle that is resting at the edge of these fan blades are on the circle generated by the radius. We are told that the mass of it is one g or .001 kg. And we are tasked with finding what the radial acceleration is experienced by the particle. Now we have a formula for this. This is gonna be equal to the velocity squared over the radius. But what is our velocity here? More velocity is going to be equal to two pi times our radius all over T. But what is T here? Well, T. Is in reference to the speed right at which the the fan blades are rotating the period here. Now the period is just going to be one over the frequency. But the frequency is in. Let's see here, revolutions per second. So we'll have to convert this to find T. But once we find T, we'll find V. And once we find V, we'll find a C. So let's start from the beginning here. First and foremost, we need to convert our revolutions per minute. Two revolutions per second. So we have revolutions per one minute and in one minute we have seconds. So this is going to equal revolutions per second. Great. So now let's go ahead and find T. T. is going to be one over r frequency that we just found of 20. This gives us 0.05 seconds. With that we can go ahead and find our velocity here. Which is going to be two pi times R radius of 20.6. All divided by 0.5. Giving us a velocity of 75.4 m per second. Now that we have our velocity we can find our angular. Sorry, our centripetal acceleration here we have a C. Is equal to 75.4 squared, all divided by 0.6. Giving us a final answer of 9.5 times 10 to the third meters per second squared corresponding to our answer choice of B. Thank you all so much for watching. Hope this video helped. We will see you all in the next one.
Related Practice
Textbook Question
The earth has a radius of 6380 km and turns around once on its axis in 24 h. (a) What is the radial acceleration of an object at the earth's equator? Give your answer in m/s2 and as a fraction of g.
1664
views
Textbook Question
The earth has a radius of 6380 km and turns around once on its axis in 24 h. (b) If arad at the equator is greater than g, objects will fly off the earth's surface and into space. (We will see the reason for this in Chapter 5.) What would the period of the earth's rotation have to be for this to occur?
2928
views
Textbook Question
A model of a helicopter rotor has four blades, each 3.40 m long from the central shaft to the blade tip. The model is rotated in a wind tunnel at 550 rev/min. (a) What is the linear speed of the blade tip, in m/s?
2343
views
Textbook Question
At its Ames Research Center, NASA uses its large '20-G' centrifuge to test the effects of very large accelerations ('hypergravity') on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge's arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. (a) How fast must the astronaut's head be moving to experience this maximum acceleration?
906
views
Textbook Question
The coordinates of a bird flying in the xy-plane are given by x(t) = αt and y(t) = 3.0 m − βt2, where α = 2.4 m/s and β = 1.2 m/s2. (c) Calculate the magnitude and direction of the bird's velocity and acceleration at t = 2.0 s.
2655
views
2
rank
Textbook Question
A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by v = [5.00 m/s − (0.0180 m/s3)t2]î + [2.00 m/s + (0.550 m/s2)t]ĵ. (b) What are the magnitude and direction of the car's velocity at t = 8.00 s? (b) What are the magnitude and direction of the car's acceleration at t = 8.00 s?
1657
views