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Ch 03: Motion in Two or Three Dimensions
Chapter 3, Problem 3

A river flows due south with a speed of 2.0 m/s. You steer a motorboat across the river; your velocity relative to the water is 4.2 m/s due east. The river is 500 m wide. (b) How much time is required to cross the river?

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1
Identify the velocity of the motorboat relative to the water, which is given as 4.2 m/s due east. This is the velocity component perpendicular to the river flow.
Recognize that the river's flow velocity (2.0 m/s due south) does not affect the time taken to cross the river, as it only affects the boat's displacement along the river, not across it.
Understand that the time to cross the river depends solely on the width of the river and the eastward velocity component of the boat relative to the water.
Calculate the time required to cross the river using the formula: time = distance / velocity. Here, the distance is the width of the river (500 m) and the velocity is the eastward component of the boat's velocity (4.2 m/s).
Substitute the values into the formula to find the time required to cross the river.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Relative Velocity

Relative velocity refers to the velocity of an object as observed from a particular reference frame. In this scenario, the motorboat's velocity is given relative to the water, while the river's current affects its overall path. Understanding how to combine these velocities is crucial for determining the boat's effective speed across the river.
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Intro to Relative Motion (Relative Velocity)

Vector Addition

Vector addition is the process of combining two or more vectors to determine a resultant vector. In this case, the motorboat's velocity vector (4.2 m/s east) and the river's current vector (2.0 m/s south) must be added to find the boat's actual trajectory. This involves using the Pythagorean theorem to calculate the resultant velocity when the vectors are perpendicular.
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Time Calculation

Time calculation in physics often involves using the formula time = distance / speed. To find the time required for the boat to cross the river, one must determine the effective speed of the boat in the direction perpendicular to the river's flow. Given the width of the river (500 m) and the component of the boat's velocity directed across the river, this formula can be applied to find the crossing time.
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Related Practice
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An airplane pilot wishes to fly due west. A wind of 80.0 km/h (about 50 mi/h) is blowing toward the south. (a) If the airspeed of the plane (its speed in still air) is 320.0 km/h (about 200 mi/h), in which direction should the pilot head?
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Textbook Question
A canoe has a velocity of 0.40 m/s southeast relative to the earth. The canoe is on a river that is flowing 0.50 m/s east relative to the earth. Find the velocity (magnitude and direction) of the canoe relative to the river.
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Textbook Question
A river flows due south with a speed of 2.0 m/s. You steer a motorboat across the river; your velocity relative to the water is 4.2 m/s due east. The river is 500 m wide. (a) What is your velocity (magnitude and direction) relative to the earth?
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Textbook Question
A 'moving sidewalk' in an airport terminal moves at 1.0 m/s and is 35.0 m long. If a woman steps on at one end and walks at 1.5 m/s relative to the moving sidewalk, how much time does it take her to reach the opposite end if she walks (a) in the same direction the sidewalk is moving?
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Textbook Question
A 'moving sidewalk' in an airport terminal moves at 1.0 m/s and is 35.0 m long. If a woman steps on at one end and walks at 1.5 m/s relative to the moving sidewalk, how much time does it take her to reach the opposite end if she walks (b) In the opposite direction?
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Textbook Question
A dog running in an open field has components of velocity υx = 2.6 m/s and υy = −1.8 m/s at t1 = 10.0 s. For the time interval from t1 = 10.0 s to t2 = 20.0 s, the average acceleration of the dog has magnitude 0.45 m/s2 and direction 31.0° measured from the +x–axis toward the +y–axis. At t2 = 20.0 s, (a) what are the x- and y-components of the dog's velocity?
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