A Fast Pitch. The fastest measured pitched baseball left the pitcher's hand at a speed of 45.0 m/s. If the pitcher was in contact with the ball over a distance of 1.50 m and produced constant acceleration, (a) what acceleration did he give the ball?

Video transcript

Welcome back, everyone. We are making observations about a bowler during a cricket match. We are told that a bowler releases the ball at a speed of 144 kilometers divided by one hour. Now, initially, we are told that the bowler is at rest and we assume that the bowler applies constant acceleration to the ball while running over a distance of 2 m. Now, we are tasked with finding what is the acceleration that the bowler supplies to the ball. Now, before getting started here, I do wish to acknowledge the multiple choice answers on the left hand side of the screen. Those are gonna be the values in which we strive for. So without further ado let us begin. All right. Well, I'm looking at our problem and I see that we need to find acceleration. We have values like delta XV, I and VF. What this is telling me is that we need to use our kinematic formulas. The kinematic formula that fits this situation is as follows. Our final velocity squared is equal to our initial velocity squared plus two times our acceleration multiplied with our delta X. Let me go ahead and subtract our initial velocity squared from both sides. You'll see on the right hand side, our initial velocities cancel out. And then what I can do is I can divide both sides by two delta X. And you'll see on the right hand side of our equation, the twos cancel out and the delta X is cancel out. What this leaves us with is that our acceleration is equal to our final velocity squared minus our initial velocity squared divided by two times delta X. Let's go ahead and plug in these values. We have 40 squared minus zero squared divided by two times two. And what this leaves us with is that our acceleration is 400 m per second squared corresponding to our final answer. Choice of D Thank you all so much for watching. I hope this video helped. We will see you all in the next one.