Skip to main content
Ch 17: Superposition

Chapter 17, Problem 17

A flutist assembles her flute in a room where the speed of sound is 342 m/s . When she plays the note A, it is in perfect tune with a 440 Hz tuning fork. After a few minutes, the air inside her flute has warmed to where the speed of sound is 346 m/s. b. How far does she need to extend the 'tuning joint' of her flute to be in tune with the tuning fork?

Verified Solution
Video duration:
3m
This video solution was recommended by our tutors as helpful for the problem above.
548
views
Was this helpful?

Video transcript

Hey, everyone. So this problem is dealing with open open air columns. Let's see what it's asking us. A musician adjusts the length of his instrument to produce a fundamental frequency of exactly Hertz on a day when the speed of sound in the air was 343 m per second. But the concert was held on a different day when the speed of sound was only 338 m per second. How much should the musician ad adjust the length of his musical instrument, which is an open open air column to obtain the same frequency. And so our multiple choice answers are if the length should be decreased by 5. millimeters or 1.8 millimeters, or if the length should be increased by 1.8 millimeters or 5.1 millimeters. So the first thing that we can due for this problem is recalled that the frequency in an open open two is given by the equation F equals N V divided by two L. And we're told that it's the fundamental frequency. So we know that N equals one solving for and substituting one for N, we have L equals B divided by two F. So on that first day, we can solve for the length of this instrument. So we call that the initial length. So the speed of sound was 343 m per second, divided by two, multiplied by our frequency Hertz. We plug that in and we get a length of 0.3472 m. Now the day of the concert, we'll call that our final place. The speed was decreased to 338 m per second. And our frequency is the same as the goal, right? What length do we need to get the same frequency? So that's 494 Hertz and he gets 0. m. And so the final step is just going to be to subtract our initial length from our final length and we get negative 5.1 millimeters. And so it's negative. That means it should be decreasing, the length should be decreasing by 5.1 million years. And that aligns with answer choice A so that's all we have for this one. We'll see you in the next video.
Related Practice
Textbook Question
A 280 Hz sound wave is directed into one end of the trombone slide seen in FIGURE P17.55. A microphone is placed at the other end to record the intensity of sound waves that are transmitted through the tube. The straight sides of the slide are 80 cm in length and 10 cm apart with a semicircular bend at the end. For what slide extensions s will the microphone detect a maximum of sound intensity?

570
views
Textbook Question
A 1.0-m-tall vertical tube is filled with 20°C water. A tuning fork vibrating at 580 Hz is held just over the top of the tube as the water is slowly drained from the bottom. At what water heights, measured from the bottom of the tube, will there be a standing wave in the tube above the water?
737
views
Textbook Question
An old mining tunnel disappears into a hillside. You would like to know how long the tunnel is, but it's too dangerous to go inside. Recalling your recent physics class, you decide to try setting up standing-wave resonances inside the tunnel. Using your subsonic amplifier and loudspeaker, you find resonances at 4.5 Hz and 6.3 Hz, and at no frequencies between these. It's rather chilly inside the tunnel, so you estimate the sound speed to be 335 m/s . Based on your measurements, how far is it to the end of the tunnel?
326
views
Textbook Question
Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note A should have a frequency of 440 Hz and the note E should be at 659 Hz. c. The tuner starts with the tension in the E string a little low, then tightens it. What is the frequency of the E string when she hears four beats per second?
398
views