Skip to main content
Ch 16: Traveling Waves
Chapter 16, Problem 16

An avant-garde composer wants to use the Doppler effect in his new opera. As the soprano sings, he wants a large bat to fly toward her from the back of the stage. The bat will be outfitted with a microphone to pick up the singer's voice and a loudspeaker to rebroadcast the sound toward the audience. The composer wants the sound the audience hears from the bat to be, in musical terms, one half-step higher in frequency than the note they are hearing from the singer. Two notes a half-step apart have a frequency ratio of 2¹/² = 1.059. With what speed must the bat fly toward the singer?

Verified step by step guidance
1
Identify the frequency ratio for a half-step increase in musical notes, which is given as 1.059.
Use the Doppler effect formula for the frequency observed by the bat as it moves towards the source of sound: \( f' = f \left(\frac{v + v_b}{v} \right) \), where \( f' \) is the frequency heard by the bat, \( f \) is the frequency of the sound emitted by the singer, \( v \) is the speed of sound in air, and \( v_b \) is the speed of the bat.
Set up the equation to solve for \( v_b \) by equating the frequency ratio to the Doppler shift formula: \( 1.059 = \frac{v + v_b}{v} \).
Rearrange the equation to solve for the bat's speed, \( v_b \): \( v_b = 0.059v \).
To find the numerical value of \( v_b \), substitute the typical speed of sound in air (around 340 m/s) into the equation.

Verified Solution

Video duration:
12m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Doppler Effect

The Doppler Effect is the change in frequency or wavelength of a wave in relation to an observer moving relative to the wave source. When the source of sound moves toward an observer, the sound waves are compressed, resulting in a higher frequency. Conversely, if the source moves away, the waves are stretched, leading to a lower frequency. This phenomenon is crucial for understanding how the bat's movement affects the frequency of the sound heard by the audience.
Recommended video:
Guided course
07:40
The Doppler Effect

Frequency and Musical Intervals

Frequency refers to the number of cycles of a wave that occur in a second, measured in Hertz (Hz). In music, different frequencies correspond to different pitches, and musical intervals describe the relationship between these pitches. A half-step interval, for example, corresponds to a frequency ratio of approximately 1.059, meaning that to achieve a half-step increase in pitch, the frequency must be multiplied by this ratio. Understanding this relationship is essential for calculating the required frequency change in the sound heard by the audience.
Recommended video:
Guided course
05:08
Circumference, Period, and Frequency in UCM

Relative Velocity

Relative velocity is the velocity of an object as observed from a particular reference frame, which can differ from its actual velocity in a stationary frame. In the context of the Doppler Effect, the speed of the bat relative to the soprano affects the frequency of the sound waves reaching the audience. To determine the speed at which the bat must fly to achieve the desired frequency shift, one must consider both the speed of sound in air and the bat's velocity toward the singer.
Recommended video:
Guided course
04:27
Intro to Relative Motion (Relative Velocity)
Related Practice
Textbook Question
Show that the displacement D(x,t) = cx² + dt², where c and d are constants, is a solution to the wave equation. Then find an expression in terms of c and d for the wave speed.
386
views
Textbook Question
A sound wave is described by D (y,t) = (0.0200 mm) ✕ sin [(8.96 rad/m)y + (3140 rad/s)t + π/4 rad], where y is in m and t is in s. b. Along which axis is the air oscillating?
431
views
Textbook Question
One cue your hearing system uses to localize a sound (i.e., to tell where a sound is coming from) is the slight difference in the arrival times of the sound at your ears. Your ears are spaced approximately 20 cm apart. Consider a sound source 5.0 m from the center of your head along a line 45° to your right. What is the difference in arrival times? Give your answer in microseconds. Hint: You are looking for the difference between two numbers that are nearly the same. What does this near equality imply about the necessary precision during intermediate stages of the calculation?

449
views
Textbook Question
What is the speed of sound in air (a) on a cold winter day in Minnesota when the temperature is -25°F, and (b) on a hot summer day in Death Valley when the temperature is 125°F?
486
views
Textbook Question
Show that the displacement D(x,t) = ln(ax + bt), where a and b are constants, is a solution to the wave equation. Then find an expression in terms of a and b for the wave speed.
301
views
Textbook Question
Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note A should have a frequency of 440 Hz and the note E should be at 659 Hz. a.What is the frequency difference between the third harmonic of the A and the second harmonic of the E?
311
views