Skip to main content
Ch 15: Oscillations

Chapter 15, Problem 15

Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball in its socket. If the mass of the eyeball is 7.5 g, a typical value, what is the effective spring constant of the musculature that holds the eyeball in the socket?

Verified Solution
Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
473
views
Was this helpful?

Video transcript

Hey, everyone. So this problem is dealing with simple harmonic motion. Let's submit its a, a person standing on the bridge notices that the bridge starts to vibrate with a frequency of 3.5 Hertz when a large truck passes by the mass of the bridge is 5000 kg. And then we're asked to find the effective spring constant of that bridge. Our multiple choice answers here are a 1.9 times 10 to the three Newton per meter. B 1.9 times 10 to the sixth Newton per meter. C 2.42 times 10 to the three Newton per meter or D 2.42 times 10 to the sixth Newton per meter. And so the key to solving this problem is going to be we're calling our period equation in terms of our spring constant. So that's gonna be T is equal to two pi multiplied by the square root of M divided by K, where T is our period M is our mass and K is that effective spring constant that we're solving for. In turn, we can recall that by definition, a period is just one divided by the frequency. And so when the plug that into this initial equation and square both sides, we're left with one divided by F squared equals four pi squared multiplied by M all divided by K. And again, we're solving for K, we wanna isolate that variable. And that leaves us with four pi squared and four pi squared M multiplied by F swear. And so from there, it's a simple plug-in chug using the information given to us in the problem. So we have K equals four pi squared multiplied by the mass of 5000 kg multiplied by our frequency 3.5 Hertz. And that quantity is squared. And we plug that in to our calculator and we get 2.42 times 10 to the six newtons per meter. And that aligns with answer choice T. So D is the correct answer for this problem. So that's all we have for this one. We'll see you in our next video.
Related Practice
Textbook Question
Astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating on a large spring. Suppose an astronaut attaches one end of a large spring to her belt and the other end to a hook on the wall of the space capsule. A fellow astronaut then pulls her away from the wall and releases her. The spring's length as a function of time is shown in FIGURE P15.46. b. What is her speed when the spring's length is 1.2 m?

724
views
Textbook Question
A 500 g air-track glider moving at 0.50 m/s collides with a horizontal spring whose opposite end is anchored to the end of the track. Measurements show that the glider is in contact with the spring for 1.5 s before it rebounds. a. What is the value of the spring constant?
404
views
Textbook Question
A 500 g air-track glider moving at 0.50 m/s collides with a horizontal spring whose opposite end is anchored to the end of the track. Measurements show that the glider is in contact with the spring for 1.5 s before it rebounds. b. What is the maximum compression of the spring?
783
views
Textbook Question
An ultrasonic transducer, of the type used in medical ultrasound imaging, is a very thin disk (m = 0.10 g) driven back and forth in SHM at 1.0 MHz by an electromagnetic coil. b. What is the disk's maximum speed at this amplitude?
471
views
Textbook Question
The 15 g head of a bobble-head doll oscillates in SHM at a frequency of 4.0 Hz. b. The amplitude of the head's oscillations decreases to 0.5 cm in 4.0 s. What is the head's damping constant?
374
views
Textbook Question
Suppose a large spherical object, such as a planet, with radius R and mass M has a narrow tunnel passing diametrically through it. A particle of mass m is inside the tunnel at a distance 𝓍 ≀ R from the center. It can be shown that the net gravitational force on the particle is due entirely to the sphere of mass with radius 𝓇 ≀ 𝓍 there is no net gravitational force from the mass in the spherical shell with 𝓇 > 𝓍. a. Find an expression for the gravitational force on the particle, assuming the object has uniform density. Your expression will be in terms of x, R, m, M, and any necessary constants.
397
views