Skip to main content
Ch 15: Oscillations
Chapter 15, Problem 15

A 500 g air-track glider moving at 0.50 m/s collides with a horizontal spring whose opposite end is anchored to the end of the track. Measurements show that the glider is in contact with the spring for 1.5 s before it rebounds. b. What is the maximum compression of the spring?

Verified step by step guidance
1
Determine the initial kinetic energy of the glider using the formula \( KE = \frac{1}{2} m v^2 \), where \( m \) is the mass of the glider and \( v \) is its velocity.
Assume that the kinetic energy of the glider is completely converted into potential energy of the spring at maximum compression. Use the formula for the potential energy stored in a spring, \( PE = \frac{1}{2} k x^2 \), where \( k \) is the spring constant and \( x \) is the compression of the spring.
Set the kinetic energy equal to the potential energy to form the equation \( \frac{1}{2} m v^2 = \frac{1}{2} k x^2 \).
Solve for \( x \) to find the maximum compression of the spring. Rearrange the equation to \( x = \sqrt{\frac{m v^2}{k}} \).
To find the value of \( x \), you will need the value of the spring constant \( k \), which might be given in the problem or may need to be calculated or measured from additional data.

Verified Solution

Video duration:
3m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Conservation of Momentum

The principle of conservation of momentum states that in a closed system, the total momentum before an event must equal the total momentum after the event, provided no external forces act on it. In this scenario, the momentum of the glider before it collides with the spring will be transferred to the spring and then back to the glider as it rebounds, allowing us to analyze the interaction.
Recommended video:
Guided course
05:58
Conservation Of Momentum

Hooke's Law

Hooke's Law describes the behavior of springs, stating that the force exerted by a spring is directly proportional to its displacement from the equilibrium position, expressed as F = -kx, where F is the force, k is the spring constant, and x is the displacement. This relationship is crucial for determining the maximum compression of the spring when the glider collides with it.
Recommended video:
Guided course
05:37
Spring Force (Hooke's Law)

Kinetic and Potential Energy

Kinetic energy is the energy of an object due to its motion, calculated as KE = 1/2 mv², where m is mass and v is velocity. When the glider compresses the spring, its kinetic energy is converted into potential energy stored in the spring, given by PE = 1/2 kx². Understanding this energy transformation is essential for calculating the maximum compression of the spring during the collision.
Recommended video:
Guided course
06:35
Gravitational Potential Energy
Related Practice
Textbook Question
A 100 g block attached to a spring with spring constant 2.5 N/m oscillates horizontally on a frictionless table. Its velocity is 20 c/m when 𝓍 = ─5.0 cm c. What is the block's position when the acceleration is maximum?
584
views
Textbook Question
Astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating on a large spring. Suppose an astronaut attaches one end of a large spring to her belt and the other end to a hook on the wall of the space capsule. A fellow astronaut then pulls her away from the wall and releases her. The spring's length as a function of time is shown in FIGURE P15.46. b. What is her speed when the spring's length is 1.2 m?

879
views
Textbook Question
A 500 g air-track glider moving at 0.50 m/s collides with a horizontal spring whose opposite end is anchored to the end of the track. Measurements show that the glider is in contact with the spring for 1.5 s before it rebounds. a. What is the value of the spring constant?
441
views
Textbook Question
Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball in its socket. If the mass of the eyeball is 7.5 g, a typical value, what is the effective spring constant of the musculature that holds the eyeball in the socket?
533
views
Textbook Question
An ultrasonic transducer, of the type used in medical ultrasound imaging, is a very thin disk (m = 0.10 g) driven back and forth in SHM at 1.0 MHz by an electromagnetic coil. b. What is the disk's maximum speed at this amplitude?
509
views
Textbook Question
The 15 g head of a bobble-head doll oscillates in SHM at a frequency of 4.0 Hz. b. The amplitude of the head's oscillations decreases to 0.5 cm in 4.0 s. What is the head's damping constant?
426
views