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Ch 15: Oscillations

Chapter 15, Problem 15

An ultrasonic transducer, of the type used in medical ultrasound imaging, is a very thin disk (m = 0.10 g) driven back and forth in SHM at 1.0 MHz by an electromagnetic coil. b. What is the disk's maximum speed at this amplitude?

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Hey, everyone. So this problem is dealing with simple harmonic motion. Let's see what it's asking us. We have a thin metal plate with a mass of 0.25 g experiencing oscillations. We're asked to determine the maximum speed attained by the plate given a frequency of the oscillations of 1.5 megahertz. We're also told that the plate shows a maximum acceleration of 1.4 times 10 88 m per second squared. Our multiple choice answers here are a 14.9 m per second. B 18.4 m per second, C 15.7 m per second or D 9.42 m per second. So recalling our basic equations of simple harmonic motion is going to be the key to solving this problem. So we can recall that our maximum acceleration is given by the equation A our amplitude multiple multiplied by omega squared where omega is our angular frequency. And then our maximum speed is given by simply a multiplied by omega and then omega in terms of frequency which we are given in the problem is simply two pi F and so combining these and looking at what was given to us. And the problem we have a maximum acceleration and we have a frequency so we can solve for Omega and we are looking for that maximum speed. So we can rewrite a as our maximum acceleration divided by omega squared. And then in turn, our maximum velocity becomes maximum acceleration divided by omega squared and then multiplied by omega. So one of the Omegas cancel and then we can plug in that two pi F. So we have a max divided by two if and from there, we can plug in the values from the problem. Our maximum acceleration is 1.4 times 10 to the eight meters per second squared divided by two pi multiplied by our frequency which is 1.5. Be careful with your unit. That's megahertz. So 1.5 times 10 to the six Hertz. And so when we plug that in to our populated, we get a maximum speed of 14.9 m per second. And that aligns with answer choice. A so that is the correct answer for this problem. That's all we have for this one. We'll see you in the next video.
Related Practice
Textbook Question
A 500 g air-track glider moving at 0.50 m/s collides with a horizontal spring whose opposite end is anchored to the end of the track. Measurements show that the glider is in contact with the spring for 1.5 s before it rebounds. a. What is the value of the spring constant?
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Textbook Question
A 500 g air-track glider moving at 0.50 m/s collides with a horizontal spring whose opposite end is anchored to the end of the track. Measurements show that the glider is in contact with the spring for 1.5 s before it rebounds. b. What is the maximum compression of the spring?
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Textbook Question
Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball in its socket. If the mass of the eyeball is 7.5 g, a typical value, what is the effective spring constant of the musculature that holds the eyeball in the socket?
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Textbook Question
The 15 g head of a bobble-head doll oscillates in SHM at a frequency of 4.0 Hz. b. The amplitude of the head's oscillations decreases to 0.5 cm in 4.0 s. What is the head's damping constant?
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Textbook Question
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Textbook Question
Two 500 g air-track gliders are each connected by identical springs with spring constant 25 N/m to the ends of the air track. The gliders are connected to each other by a spring with spring constant 2.0 N/m. One glider is pulled 8.0 cm to the side and released while the other is at rest at its equilibrium position. How long will it take until the glider that was initially at rest has all the motion while the first glider is at rest?
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