The concentration of Cl⁻ ion in blood is approximately 100 mEq/L. How many milliliters of blood would be needed to obtain 1.0 g of Cl⁻ ions?

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Welcome back everyone. A solution available in the laboratory contains 450 mil equivalents per liter of iodide ions. Calculate the volume in milliliters of the solution needed to provide 2. g of iodide ions. So because we need to find the volume to provide the 2.50 g of iodide ions. Our final unit should be in milliliters as stated by the prompt. So we would find that by beginning with the mass of iodide ions, 2.50 g of iodide, and we will multiply to go from grams in the denominator to then moles in the numerator. This is where we're going to recall the molar mass of iodide where for 126.9 g of iodide in the periodic table, we have that mass per mole of iodide ions. And so canceling out grams of iodide. We've got now moles of iodide in which we will multiply to go from moles in the denominator to then millimoles in the numerator. And from our textbooks, we're going to recall that our prefix Milly tells us that we have an equivalent of 10 to the negative third moles for one milli mole. So 10 to the negative third moles is in the denominator and we can then cancel out moles. Now, we will have millimoles and our next conversion factor is going to incorporate what the prompt tells us. Which is that for one liter of iodide ions, we've got 450 milli equivalents of solution. And so we will recall that one milli equivalent is actually equal to one mimmo. And so we would plug in 450 millimoles in the denominator. So canceling out minimal, we now have leaders and we can then multiply to go from leaders in the denominator to our final unit of volume milliliters where we would recall that our prefix Milly tells us we have an equivalence of 10 to the negative third leaders in the denominator. So canceling out leaders, we are left with Millis as our final unit of volume and this is going to result in the volume needed of the solution being 43.8 mL. And this will be our answer rounded to three significant figures. So 43.8 millilitres of volume of solution is required to provide 2.50 g of iodide ions. I hope this made sense and let us know if you have any questions

The concentration of Cl⁻ ion in blood is approximately 100 mEq/L. How many milliliters of blood would be needed to obtain 1.0 g of Cl⁻ ions?

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Key Concepts

Molarity and Equivalent Weight

Conversion between Mass and Moles

Volume Calculation from Concentration