Mark the chiral centers in the following molecules, if any, with an asterisk (*):

(a)

Question

Mark the chiral centers in the following molecules, if any, with an asterisk (*):

(a)

Accepted Answer

Welcome back, everyone identify the chiral centers in the molecule shown below. Label them using an asterisk. First of all, let's remember that Carol centers, those are, if we consider carbon atoms, they are carbon atoms with four different substituents. So we want to analyze the carbon atoms given to us in the structure. And we want to identify those with different substituents. If we identify two exactly same substituents, we can move on. So first of all, we can begin from the left side of the structure. We have to understand that we have a metal group. So there are three exactly same hydrogen atoms, meaning the war first carbon is not Cairo, we can skip it and then we have CH two, the implicit carbon has two bonds. So there must be additional two hydrogen atoms, we can skip it as well because it has two, exactly the same hydrogens cover number three. Now let's consider the subscriptions. There is an implicit hydrogen, let's label it. There is O hi Troy. And now if we move to the left, we have CH two bonded to carbon. If we move to the right, we have ch bonded to two carbons. So those are different, right? We have spotted the difference in our substituents. We're comparing CH two which is also bonded to C right versus CH which is also bonded to two carbons. So we can just show that hydrogen and the two carbons, those are from the muscle groups. This means that we have located the very first chiral center and we can just label it with an asterisk. And now moving on, we can see that carbon number four, it has two, exactly same methyl substi. So we can skip it right. And then of course, every methyl substi has three hygen. So those methyl groups are definitely not chiral because they have we hydrogens and those hydrogens are equivalent. So we understand that there is only one Cairo center for complete clarity. We're just going to redraw the structure and we are going to label the only chiral carbon atom present in the given structure that has four different substitutions oh hydrogen in two different alkyl groups. We can even visually see that those alkyl groups are different, right? There's definitely no necessity to think about the atoms. We can just visually compare those we have an isopropyl group and an ethyl group. Those are different. And this gives us four different substituents which makes carbon number three a chiral center. Thank you for watching.

Mark the chiral centers in the following molecules, if any, with an asterisk (*):

(a) <IMAGE>

Verified Solution

Key Concepts

Chirality

Chiral Centers

Stereochemistry