Consider rare disorders in a population caused by an autosomal recessive mutation. From the frequencies of the disorder in the population given, calculate the percentage of heterozygous carriers:

0.0064

Video transcript

Hi everyone. Here's our next question. In a population of 500 individuals, 64 are homos. I guess recessive for a particular trait. What is the frequency of the recessive allele in this population. Well looking for the frequency of the recessive allele being given the number of homes I guess recessive offspring. We're gonna use our hardy Weinberg equations. We know when it comes to the frequency of alleles P plus Q equals one. Where in this equation Q. Is the frequency of the excessive value. And then we have that Q squared is going to equal the frequency of the homocide recessive genotype? Well, we know our frequency of our home is recessive genotype because we're given the number of homicides, recessive offspring. There are. And the total population size. So Q squared or the frequency of the homosexuals? Recessive genotype must be a number of homosexuals. Recessive individuals divided by the total number in the population. So that will equal 60 for Vegas recessive individuals over 500 And that will equal 0.128. Now we just need to find out what's the frequency of our assess the value. We don't even need anything to do with P. Because we've already got Q squared. So the frequency of our assessed value is P. Is Q. Excuse me. We're looking for Q. So Q. Must equal the square root of Q squared, Which would equal the square root of 0.128. And when we played that in we get an answer of 0.36. So there's our final result. And we look at our answer choices. We see that choice c. 0.36. That would be our frequency of the recessive value. So again, in a population of 500 individuals, 60 for homos, I guess recessive. What is the frequency of the recessive alley on this population choice? T 0.36. See you in the next video.