Consider rare disorders in a population caused by an autosomal recessive mutation. From the frequencies of the disorder in the population given, calculate the percentage of heterozygous carriers:

0.09

Video transcript

Hi everybody. Here's our next problem. It says If the frequency of the recessive allele in the population is 0.2 what is the expected frequency of Hetero six individuals in the population? Let's remember that. We've got an equation for the frequency of alleles in a population were given the frequency of the al. Also always want to keep straight. Are you being given the frequency of the alley where you're being given the frequency of the genotype? In this case it's the alley. And we have the formula P plus Q equals one. Where P. Is the frequency of the dominant allele. And cue the frequency of the recessive allele. Then we also of course no we're looking for the expected frequency of Hetero six individuals. And we know that two PQ expresses the frequency of heterocyclic. It's in the population. So since we're given the frequency of the recessive value or Q. We can figure P. From that. Or calculate P. We've got p. We've got Q. We can then calculate the frequency of heterocyclic. It's so since we know that people's Q equals one, we're looking for P. We know that must be one minus Q. Which would equal one minus 0.2. Soapy must equal 0.8. Therefore our frequency of hetero cigarettes. It's two p. q. Which is equal two times 0. Time 0.2. And that's gonna equal 0.32. So we look over to answer choices. We do see that choice c. 0.32. Yeah. The other answers are incorrect. Since we have solved the problem? Oh, that didn't get any of those. So again, if the frequency of the recessive allele in the population is 0.2. What is the expected frequency of Hetero six individuals? And that would be choice C 0.32 or 32%. See you in the next video.