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Ch. 10 - DNA Structure and Analysis

Chapter 10, Problem 16

What might Watson and Crick have concluded had Chargaff's data from a single source indicated the following? A T G C % 29 19 21 31 Why would this conclusion be contradictory to Wilkins's and Franklin's data?

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Hello everyone and welcome to today's video. So an average chicken cells DNA contains 27% of adding. While will the sales side of seeing content be? In terms of percentages? Will remember that DNA is going to have four nitrogenous bases and these are going to look like this. Now if this DNA has Developing then it has to have 27% timing. Because because each adding is bound to a timing. So these two are going to add up to 54. If we subtract that from 100% we're going to get that. The remaining percentage is going to be 46%. Now the C. G. Which are the remaining two basis together are going to accomplish 46% of the remaining nucleotide sequences of D. N. A. Now C. G put together are going to be 23% C. and 23 G. And it is going to add up to the remaining 46% of the number of nucleotides left because of this. The correct answer choice is going to be a 23%. That is going to be the percentage of cytosine content left. If we have 27% adding. I really hope this video helped you and I hope to see you on the next one