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Ch.2 - Atoms & Elements

Chapter 2, Problem 35

Upon decomposition, one sample of magnesium fluoride produces 1.65 kg of magnesium and 2.57 kg of fluorine. A second sample produces 2.72 kg of magnesium. How much fluorine (in grams) does the second sample produce?

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Hi everyone for this problem we're told that two samples of calcium bromide have undergone a decomposition reaction sample A produced 2.63 kg of calcium and 10.5 kg of grooming. And we're being asked if sample be produced 3.6 kg of calcium. What is the expected mass of bro mean? Produced in kilograms. So what we can do here is we can set these ratios equal to each other to solve for our unknown. So if we set the ratio of sample A two sample B. That is going to look like this For sample a. We have 2.63 kilograms of calcium per 10.5 kilograms of browning. And if we set this equal to the ratio for sample B, we have 3. kilograms of calcium Per are unknown. Which we can set as one kilogram of bro. Mean. So essentially here what we want to do is solve for our bro, mean, and this is going to tell us what are expected masses for every one kg of bro. Mean, we want to know what is its mass. So in order to isolate this, we can cross multiply across our proportions and once we set this up will get 10.5 kg of bro, mean, Times 3.6 kilograms of calcium is equal to one kg of bro. Mean, Times 2.63 kg of calcium. Okay, now remember we are solving for one kg of bromine. So let's go ahead and isolate this out. We can divide both sides. Bye. 2.63 kg of calcium. And once we do that, we'll get our kilograms of calcium cancel each other on our right side and we're left with one kg of browning is equal to 14.4 kilograms of bro mean, and this is our final answer. This is the expected mass of bro mean produced in kilograms. That is the end of this problem. I hope this was helpful.
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