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Ch.2 - Atoms & Elements
Chapter 2, Problem 39

Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produces 3.49 g oxygen and 3.50 g sulfur, while the sulfur trioxide produces 6.75 g oxygen and 4.50 g sulfur. Calculate the mass of oxygen per gram of sulfur for each sample and show that these results are consistent with the law of multiple proportions.

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Calculate the mass of oxygen per gram of sulfur in sulfur dioxide by dividing the mass of oxygen by the mass of sulfur: \( \frac{3.49 \, \text{g O}}{3.50 \, \text{g S}} \).
Calculate the mass of oxygen per gram of sulfur in sulfur trioxide by dividing the mass of oxygen by the mass of sulfur: \( \frac{6.75 \, \text{g O}}{4.50 \, \text{g S}} \).
Compare the two ratios obtained from the calculations to determine if they are in a simple whole number ratio, which would be consistent with the law of multiple proportions.
The law of multiple proportions states that when two elements form more than one compound, the ratios of the masses of the second element that combine with a fixed mass of the first element are in simple whole numbers.
Verify that the ratio of the two calculated values is a simple whole number ratio, confirming the law of multiple proportions.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Law of Multiple Proportions

The Law of Multiple Proportions states that when two elements form more than one compound, the ratios of the masses of one element that combine with a fixed mass of the other element can be expressed as small whole numbers. This principle helps to explain the different compounds formed by sulfur and oxygen, such as sulfur dioxide and sulfur trioxide, and is essential for analyzing their mass ratios.
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Mass Ratio Calculation

To determine the mass of oxygen per gram of sulfur, one must calculate the ratio of the mass of oxygen to the mass of sulfur for each compound. This involves dividing the mass of oxygen produced by the mass of sulfur in each decomposition reaction, providing a quantitative measure that can be compared across different compounds.
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Stoichiometry

Stoichiometry is the area of chemistry that deals with the relationships between the quantities of reactants and products in chemical reactions. Understanding stoichiometry is crucial for performing calculations involving mass, moles, and ratios, which are necessary to analyze the decomposition of sulfur dioxide and sulfur trioxide in this question.
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Related Practice
Textbook Question

The mass ratio of sodium to fluorine in sodium fluoride is 1.21:1. A sample of sodium fluoride produces 45.1 g of sodium upon decomposition. How much fluorine (in grams) forms?

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Textbook Question

Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a sample of sulfur hexafluoride produces 4.45 g of fluorine and 1.25 g of sulfur, while decomposition of a sample of sulfur tetrafluoride produces 4.43 g of fluorine and 1.87 g of sulfur. Calculate the mass of fluorine per gram of sulfur for each sample and show that these results are consistent with the law of multiple proportions.

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Textbook Question

Which statements are consistent with Dalton's atomic theory as it was originally stated? Why? a. Sulfur and oxygen atoms have the same mass. b. All cobalt atoms are identical. c. Potassium and chlorine atoms combine in a 1:1 ratio to form potassium chloride. d. Lead atoms can be converted into gold.

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