Write a partial decay series for Th-232 undergoing the sequential decays: a, b, b, a.

Video transcript

Hey everyone, we're asked to identify the final new glide. If radium 2 26 undergoes the partial decay series, alpha alpha alpha beta First, we can go ahead and write out our radium 226. And if we look at our periodic table, we find that it has an atomic number of 88. It then undergoes an alpha decay. So we have our alpha particle and a four and a two To find our missing particle. We can then take our mass number of 226 from our radium and subtract four from our alpha particle. This will get us to a value of 222 and taking our 88 from our radium and subtracting R two from r alpha particle for atomic numbers, we end up with a value of 86 which means our element comes up to raid on Next, taking our rate on 222. It then undergoes another alpha decay. We're going to do the exact same steps as we did before and take 222 and subtract before. We then end up with a value of 2 18 And we take our 86 and subtract the two and we end up with a value of 84, which means our element comes up to polonium Taking our Polonium 2 18, we then undergo another alpha decay and we're going to do the exact same steps as we did previously. So taking our 2 18 from our polonium and subtracting it from the four for alpha particle. We end up with a mass number of 2, 14, doing the same steps for our atomic number. We take our 84 and subtract our two. So we end up with a value of 82, which means our element comes up to lead, Taking our lead to 14. It then undergoes a beta decay. So we have our beta particle and we have R0 and R -1. So this time we're going to take our 2 14 and subtract R zero, which means we'll still have a mass number of 2 14. And we're going to take our 82 and subtract that negative one. So we end up with an atomic number of 83, which means our element comes up to bismuth. So our final new glide comes up to Bismuth 2 14. So I hope this made sense. And let us know if you have any questions.