Predict the conditions (high temperature, low temperature, all temperatures, or no temperatures) under which each reaction is spontaneous. d. 2 NO₂(g) → 2 NO(g) + O₂(g) (endothermic)

Video transcript

Hello. Everyone in this video, we're trying to protect which temperature condition that this reaction needs to be spontaneous. Well, this reaction is eggs are thermic, as it says in the problem for a reaction to be exact thermic assigned for our delta H. It's going to be negative. All right now, we need to find the sign of our delta S. So what is that? Well, let's take a look at our reaction. Right here we have our two C. O. There's a gas plus R. +02 gas. And that's going to go ahead and react to create two moles of carbon dioxide, which of course a gas. So for my starting materials here, we have two moles of that gas from our C. O. And one mole of CO two gas. So we have three in the starting material side by the product side, we just have our two moles of our gas. So, because our starting materials has three moles of gas and that's more than two assigned for delta S. Is going to be negative. So since we have so we have negative delta each and we have a negative DELTA S. In that case, then their reaction is only going to be a spontaneous at low temperatures. So whenever we know that we have a negative DELTA H. And a negative DELTA S. The reaction will only be spontaneous when we're under low temperature conditions. So this is going to be my final answer for this problem