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Ch.12 - Liquids, Solids & Intermolecular Forces

Chapter 12, Problem 68

Calculate the amount of heat required to completely sublime 50.0 g of solid dry ice (CO2) at its sublimation temperature. The heat of sublimation for carbon dioxide is 32.3 kJ/mol.

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Hello. Everyone in this video, we're trying to calculate the amount of heat for the sublimation of 33.50 g of ammonia. So, we also have some given information. So the first thing that we're given is that the land heat of sublimation of ammonia is equal to this value right here. Another thing that's not told to us, but we can easily calculate is going to be the molar mass of ammonia. All right. And the molar mass of Ammonia is it is going to equal to 17.03 g Permal. So again, we have this piece of giving information and we found this on the side. All right. So to calculate for the amount of heat of sublimation, there's a formula. That formula is going to be Q equals M. L. So using this formula, my mass, that's going to be 33.5 grams. Then I'm going to go ahead and convert this grams to moles by using the molar mass which we have over here. So To cancel the g, I'll put 17.3 g on the bottom and on top. My numerator will be just be one more. Then what you can do next is canceling out the moles to get our killer jewels. We'll go ahead and use that given land heat of sublimation And to cancel out the most. We'll put one more on the dominator On top, we'll have 28 .97 Killer Jewels. As you can see here that the grams will cancel out moles will cancel out given us if you put everything here until the calculator. you got a Q value Of 56.99 killer jewels. And that's actually going to be our final answer, Which is the amount of heat for the sublimation of 33.5 programs of ammonia. Thank you all so much for watching.