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Ch.21 - Organic Chemistry

Chapter 21, Problem 58c

What are the products of each alkene addition reaction? c.

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Welcome back, everyone determine the plausible product of the addition reaction of the L kine given below. Ignore stereo chemistry. Let's recall that whenever we are dealing with an addition reaction starting with NLK, we want to follow the Markov Neko rule. And the Menik rule tells us that if we are adding a structure that has hydrogen and halogen specifically, we have to identify the double bonded carbons. One of our double bonnet carbon atoms has two hydrogens and the other one has one implicit hydrogen and one carbon bonnet set. So we call the left one a more substituted one, let's use M and the right one, a less substituted right now, according to the more cogni of rule, we are going to add the halogen to the more substituted carbon. So let's go ahead and do that. We are simply redrawing our carbon chain. And what we're going to do from here is just add the halogen to the more substituted carbon. And we're also going to add hydrogen to the less substituted carbon. That's what the Makoko rule states. However, there is no necessity to show that hydrogen, right, essentially, if we have a solid line it implies a methyl group at the end which has three hydrogens bonded to carbon. We're also breaking the double bond, right, specifically, we're breaking the pi bond because that's the addition reaction, the formation of two sigma bonds results in the cleavage of that pi bond. And therefore, we have our product. We simply want to draw the remaining ethyl substituents within our structure. And that said based on the me Koko's rule, we have added the BROMO group to carbon number two and hydrogen to carbon number one based on their substitution pattern. Thank you for watching.