Skip to main content
Ch.21 - Organic Chemistry

Chapter 21, Problem 91c

Name each compound. c.

Verified Solution
Video duration:
3m
This video solution was recommended by our tutors as helpful for the problem above.
253
views
Was this helpful?

Video transcript

Hey everyone where us provide the name of the following alcohol. Now, since we have an alcohol, this means our suffix is going to be O. L. Now let's go ahead and count our longest carbon chain. So looking at our structure, we can number this as 1234, 5, 6 and seven. Now, if we want a different route, like let's say we went 12345 and six, we find that our seven carbon chain is still going to be the longest and since we have that seven carbon chain, this means that our prefix is going to be helped. Now let's go ahead and determine the location of our alcohol. As we can see right here, our alcohol is at carbon number four. So when we name this, we're going to have four dash helped tunnel since the suffix of O. L. Tells us that we have an alcohol and the number four tells us that it's at our carbon number four in our seven carbon chain. Now, let's go ahead and look at our substitue ints. Looking at our substitue ints we can see that they are located at carbons number three and carbon number four. Now, let's say we had numbered our carbon chain the other way from right to left. So I'll number it in red. So we have 123456 and seven. As we can see right here, our substitue ints would have been located our carbons number four and carbon number five. And we've learned that our substitue ints must always be numbered at the lowest number possible. So our carbons number three and number four are lower values than our carbon number four and carbon number five. So we have to number our carbon chain from left to right now to Neymar substitue ints, we're going to denote those two methyl groups by adding a three comma four to say that it is on our carbons three and four. And we're going to add a dash and right dimethyl, which tells us that we have one metal on carbon number three and one metal on carbon number four. And we're going to add a dash in between R four and r dimethyl. So the complete name of our structure is going to be dimethyl for HEP channel. Now, I hope that made sense. And let us know if you have any questions.