Draw the structure of each carboxylic acid or ester. b. methyl hexanoate

Video transcript

welcome back everyone in this example, we need to draw the bond line structure for the compound ethyl butyrate. So our first step is to focus on our root and root modifier for this given name. So according to the prompt, we have the root beauty. So recall that Beauty tells us we have specifically a four carbon chain, alcohol or four carbon alcohol chain. Where we recall that an L. Kill chain is just another word for an R. Group or a carbon bonded to a series of carbons bonded to hydrogen in a train. Now our route modifier comes from this ending rate where we're going to recall that. This refers to our priority group on our main chain, which would be our car box cilic or actually car box a late since this is not an acid. So our car box a late group and recalling what this group appears as we're going to have an alcohol chain or in our group where we have that bonded to a carbon that is double bonded to an oxygen, known as a carbon deal. And then this carbon is bonded to an oxygen atom where we have another connection to an R group for the rest of our alcohol chain. But the main part of this group is just going to be this entire part of the structure here. So to be clear, our car Boxley is this side. And then on this side we have our alcohol chain. So let's draw in what we understand so far right now, we understand that we have our main carbon chain which is a four carbon L. Kill chain. So we have, we recall that each corner of a bond line structure represents a carbon atom. So we have one carbon atom here bonded to a second carbon atom. We have a third carbon atom. And then we have our fourth carbon atom. Where as we stated, our carb oxalate group, which is our root modifier, signals our priority group in the structure meaning since this is a priority group, we want it numbered at the lowest numbered carbon. And so if this entire portion is our carbon chain, we can now begin our car box elite group where we have our carbon double bonded to oxygen, forming a carbon Neil and then we continue on to form our bond to oxygen where we will have our second R group for the rest of our chain. And the second R group is going to be coming from the beginning of the name given in the prompt which is ethyl recall that ethel is just a substitute group. And this substitution group is defined by CH two CH 3 as the formula. And so that's going to appear as this oxygen being bonded to a carbon that is bonded to two hydrogen that are implied where this carbon is then bonded to another carbon where we end off our structure because this carbon is bonded to three hydrogen, recall that carbons to be stable and happy should have four bonds. And so and let's actually make this portion here neater. So this is actually going to complete our structure, our bond line structure for ethyl butyrate. We have this entire structure that we've drawn in. So just to reiterate we have our four carbon alcohol chain here where each corner is one carbon atom, so we have 1234 carbon atoms. And then we have our carb oxalate group defined by this carbon feel bonded to an oxygen bonded to our our group. And then we have our second R group which is our substitute quint being our ethyl group here. Ch two c H three where the hydrogen are implied. So what's boxed in yellow is our final answer. I hope everything I reviewed was clear. If you have any questions, lead them down below and I will see everyone in the next practice video.