Skip to main content
Ch.13 - Solutions

Chapter 13, Problem 112

Magnesium citrate, Mg3(C6H5O7)2, belongs to a class of laxatives called hyperosmotics, which cause rapid emptying of the bowel. When a concentrated solution of magnesium citrate is consumed, it passes through the intestines, drawing water and promoting diarrhea, usually within 6 hours. Calculate the osmotic pressure of a magnesium citrate laxative solution containing 28.5 g of magnesium citrate in 235 mL of solution at 37 °C (approximate body temperature). Assume complete dissociation of the ionic compound.

Verified Solution
Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
1673
views
Was this helpful?

Video transcript

Hello everyone today. We have been given the following problem and asked to solve for it Says assuming complete dissociation, calculate the osmotic pressure of magnesium acetate, abbreviated as such solution containing 52.1 g of magnesium citrate 352 ml of solution at 29°C. First you want to make note of the molar mass of magnesium citrate Which can be simplified to 142.4 g per mole. Next we want to take the amount of citrate that we actually have 52.1 g and transforms into moles by multiplying by the molar mass ratio. Our units are going to cancel and we're going to be left with 0. moles of Magnesium citrate. We now want to take our volume which is 352 ml and convert that into leaders. So we'll use the conversion factor That one mil leader is equal to 10 to the negative. 3rd leaders giving us 0.352 leaders. And now we can solve for malaria. So we take our polarity which is moles over L will take 0.366 moles And we'll divide that by 0.352 leaders to give us 1.04 m. And now we can use our osmotic osmotic pressure equation which is the osmotic pressure is equal to I or the Vantaa factor times polarity times r gas constant times our temperature. Now I is going to be three due to magnesium citrate dissociating into one magnesium and two citrate ions. So we have three overall Are malaria is 1.04. R. gas constant is 0.08-1 And our temperature is in C., but we want it in Kelvin, so we're just going to take the degrees in C and add 273.15 Kelvin. This gives us a final answer of 77. atmospheres. I hope this helped, and until next time.
Related Practice
Textbook Question

The Safe Drinking Water Act (SDWA) sets a limit for mercury—a toxin to the central nervous system—at 0.0020 ppm by mass. Water suppliers must periodically test their water to ensure that mercury levels do not exceed this limit. Suppose water becomes contaminated with mercury at twice the legal limit (0.0040 ppm). How much of this water would a person have to consume to ingest 50.0 mg of mercury?

2219
views
Textbook Question

Water softeners often replace calcium ions in hard water with sodium ions. Since sodium compounds are soluble, the presence of sodium ions in water does not cause the white, scaly residues caused by calcium ions. However, calcium is more beneficial to human health than sodium because calcium is a necessary part of the human diet, while high levels of sodium intake are linked to increases in blood pressure. The U.S. Food and Drug Administration (FDA) recommends that adults ingest less than 2.4 g of sodium per day. How many liters of softened water, containing a sodium concentration of 0.050% sodium by mass, would a person have to consume to exceed the FDA recommendation? (Assume a water density of 1.0 g>mL.)

1517
views
Textbook Question

An isotonic solution contains 0.90% NaCl mass to volume. Calculate the percent mass to volume for isotonic solutions containing each solute at 25 °C. Assume a van't Hoff factor of 1.9 for all ionic solutes. a. KCl

2015
views
Textbook Question

When HNO2 is dissolved in water, it partially dissociates according to the equation HNO2ΔH+ + NO2- . A solution is prepared that contains 7.050 g of HNO2 in 1.000 kg of water. Its freezing point is -0.2929 °C. Calculate the fraction of HNO2 that has dissociated.

2984
views
Textbook Question

A solution of a nonvolatile solute in water has a boiling point of 375.3 K. Calculate the vapor pressure of water above this solution at 338 K. The vapor pressure of pure water at this temperature is 0.2467 atm.

2683
views
1
comments
Textbook Question

The density of a 0.438 M solution of potassium chromate (K2CrO4) at 298 K is 1.063 g>mL. Calculate the vapor pressure of water above the solution. The vapor pressure of pure water at this temperature is 0.0313 atm. (Assume complete dissociation of the solute.)

1380
views
1
rank