Hydrazine, a component of rocket fuel, undergoes combus- tion to yield N2 and H2O:
N2H41l2 + O21g2 S N21g2 + 2 H2O1l2 (b) Use the following information to set up a Hess's law cycle, and then calculate ΔH° for the combustion reac- tion. You will need to use fractional coefficients for some equations.
2 NH31g2 + 3 N2O1g2 S 4 N21g2 + 3 H2O1l2
ΔH° = - 1011.2 kJ N2O1g2 + 3 H21g2 S N2H41l2 + H2O1l2
ΔH° = - 317.2 kJ 4 NH31g2 + O21g2 S 2 N2H41l2 + 2 H2O1l2
ΔH° = - 286.0 kJ
H2O1l2 ΔH°f = - 285.8 kJmol

Question

Hydrazine, a component of rocket fuel, undergoes combus- tion to yield N2 and H2O:
N2H41l2 + O21g2 S N21g2 + 2 H2O1l2 (b) Use the following information to set up a Hess's law cycle, and then calculate ΔH° for the combustion reac- tion. You will need to use fractional coefficients for some equations. 
2 NH31g2 + 3 N2O1g2 S 4 N21g2 + 3 H2O1l2 
ΔH° = - 1011.2 kJ N2O1g2 + 3 H21g2 S N2H41l2 + H2O1l2 
ΔH° = - 317.2 kJ 4 NH31g2 + O21g2 S 2 N2H41l2 + 2 H2O1l2 
ΔH° = - 286.0 kJ 
H2O1l2 ΔH°f = - 285.8 kJ>mol

Accepted Answer

Hi everyone here we have a question asking us to determine the entropy of the reaction. Using hess's law, silver oxide solid plus to hydrochloric acid. Aquarius forms to silver chloride solid plus hydrogen gas plus oxygen gas. So we're given the following data and let's go through each of these. So we have two silver solid plus half oxygen gasses forms silver oxide solid And are in the play is -31.1 kg per mole for this. To match our original equation, we need that reversed. So that's going to be 31.1 killed joules per mole. Next we have silver solid plus half chlorine. Gashes Forms silver chloride solid and the entropy is negative 127.0 killed joules per mole. And for that to match we need to multiply by two. So its entropy is going to be negative. 254 zero killed joules per mole. Next we have water liquid plus chlorine gasses forms to hydrochloric acid. Aquarius Plus half oxygen gasses and its entropy is negative 48.6 kg per mole. And we need that reversed. So that is 48 0.6 kill jules, Permal. And lastly we have hydrogen gasses plus oxygen gasses forms Water liquid and its entropy is negative 285.8 killed joules per mole. And we need that reversed. So that is 285 .8 killed joules per mole. So now let's look at what we have. We have silver oxide forms two silver plus half oxygen. We have two silver plus coring, forms two silver chloride. We have to hydrochloric acid plus one half oxygen forms water plus scoring. And we have water forms hydrogen and oxygen. So our two silver are going to cancel out. Our half oxygen are going to cancel out. Our chlorine are going to cancel out and our waters are going to cancel out. And that's going to leave us with silver oxide, solid plus to hydrochloric acid. A quiz forms two silver chloride plus hydrogen plus oxygen. So our entropy Is going to equal 31 .1 killed jules Permal plus Negative, zero Killer Jewels, thermal plus 48 0. kill jules per mole plus 0.8 kg joules per mole and that equals 111.5 kill jules Permal. And that is our final answer. Thank you for watching. Bye.

Verified Solution

Key Concepts

Hess's Law

Standard Enthalpy of Formation (ΔH°f)

Combustion Reaction