Values of Ea = 6.3 kJ>mol and A = 6.0 * 108>1M # s2 have been measured for the bimolecular reaction: NO1g2 + F21g2S NOF1g2 + F1g2 (b) The product of the reaction is nitrosyl fluoride. Its formula is usually written as NOF, but its structure is actually ONF. Is the ONF molecule linear or bent?

Video transcript

Hello. In this problem, we are told that carbonnel sulfide is produced from a biomolecular reaction between carbon monoxide and sulfur dioxide were given the activation energy and the Iranians constant. These two values are not made use of within this problem we're told the formula for the product is written as C E O. S. But its structures O C. S. Were asked what is the geometry of carbon sulfide. So to determine the geometry, we first need to draw the lewis thought structure We call when we draw lewis. we have to account for the number of valence electrons. We have oxygen which is in group six a. And it has six valence electrons. Remember the number of valence electrons is the same as the group number we have carbon which is in group four A. It has four valence electrons. And we have sulfur which is in group six A. It has six valence electrons. According to the octet rule, Most things are trying to acquire an octet to be stable. Like the noble gasses. In order for oxygen to acquire an octet has to gain two more electrons. So it typically forms two bonds. Carbon which has four valence electrons needs four more to have eight. So it typically forms four bonds and sulfur has six valence electrons. So it will gain two electrons in order to acquire an octet. We call that elements in period three, which is where sulfur is and beyond can have expanded valence shells. So it could be possible for sulfur to have more than eight electrons around it in order to um then draw the lewis dot structure. We have to determine what element goes in the center. The central element is usually the least electro negative and it is generally the one that forms more bonds. So as we look above, we see that carbon Generally forms four bonds. And if we recall the transfer electro negativity, electro negativity increases as we go up and from left to right across the periodic table. So carbon is the least electro negative and it is the one that it forms the most bonds. So we'll put carbon in the center of our skeletal structure and oxygen and sulfur around it. Next then we have a method that we can use as long as we are obeying the octet rule. It's called the need double and share method. So the need comes about from most things trying to acquire an octet to be stable. So we have oxygen, carbon and sulfur all trying to acquire eight valence electrons. So that's a total of 24 electrons that are needed number available come from the valence electrons as we've talked about above. So we have six for oxygen for for carbon And six for Sulfur. So that's a total of 16. And so we need more than are available. So the difference between those two will tell us how many to share and so we're going to share eight valence electrons. So when we share these go between the elements, so we have 2468 that are being shared. We have to account for all 16 and so we've accounted for eight of the 16. We have eight more electrons to account for those remaining eight, then go around the outer elements to fulfill their octet. So oxygen here had to four in the bonds. And so it needed four more to fill its octet, sulfur has four within the bonds. And so it also needs four more to fulfill its octet. And carbon was satisfied with the four bonds. Now to determine the geometry, we need to focus on the central element, just carbon. And we look at how many groups of electrons are around the central element. So we have one grouping of electrons here and another here. And so we have two groups of electrons around the central element. When we have two groups around the central element, the geometry is linear and so this flies in a straight line. So the um molecular geometry and also the, what we call the electron domain geometry is linear. For carbonnel sulfide. Thanks for watching. Hope you found this to be helpful